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maw [93]
3 years ago
5

The company A produces products a, and the company B produces products b. It is known that 3 percent of companies that produce p

roducts a go bankrupt over the year. Plus, the probability for companies producing products b to go bankrupt over the year is 6.1. What is the probability (given in decimal number) that both companies are going bankrupt over the year?
Mathematics
1 answer:
jeka943 years ago
5 0

Answer:

0.00183

Step-by-step explanation:

The two companies produce different products and the chance to go bankrupt will be different based on the product made. So, the probability of the company A and B to go bankrupt is independent.  

To find the answer of this question, we just need to multiply the probability to go bankrupt of each company. The calculation will be:

P(A=bankrupt) * P(B=bankrupt)= 3% * 6.1% =0.183%= 0.00183

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Convert 48°36'12" to the nearest thousandth of a degree
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3 years ago
What should be the value of x so that the three consecutive terms will be in GP 2x+2, 16 and 64x. Also find the sum of first 10
Alexxandr [17]

Answer:

<em>x = 1 and -2</em>

<em>Sum of the first ten terms = 1,398,100</em>

Step-by-step explanation:

Given the geometric progression 2x+2, 16, 64x...

Since they are in GP, their common ratio is expressed as;

16/2x+2 = 64x/16

16/2(x+1) = 4x

8/x+1 = 4x

Cross multiply

4x(x+1) = 8

4x²+4x = 8

4x²+4x - 8 = 0

divide through by 4

x²+x - 2 = 0

Factorize

x²+2x-x- 2 = 0

x(x+2)-1(x+2) = 0

(x-1)(x+2) = 0

x = 1 and -2

Hence the values of x are 1 and -2

Get the common ratio;

r = 16/2x+2

Since x = 1

r = 16/2(1)+2

r = 16/4

r = 4

Sum of the first n terms is expressed as;

Sn = a(rⁿ-1)/r-1

a = 2x+2

a = 2(1)+2

a = 4

Substitute;

S10 = 4(4^10 - 1)/4 - 1

S10 = 4(1,048,576-1)/3

S10 = 4,194,300/3

S10 = 1,398,100

Hence the sum of the first ten terms is 1,398,100

5 0
3 years ago
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