Let the value of the vehicle be described by the equation
V = a + bx
where x = number of years since purchase
a,b are constants.
When x = 0, V = $7500. Therefore
a + b*0 = 7500
a = 7500
When x = 7, V = $500. Therefore
7500 + 7b = 500
7b = 500 -7500 = -7000
b = -7000/7 = -1000
The equation is
V = 7500 - 1000x
The slope of this equation is the depreciation rate, and it is -$1000 per year.
Answer: $1000 depreciation per year.
Answer:
24.61%
Step-by-step explanation:
The distance covered in first week = 195 miles
The distance covered in the second week = 243 miles
We need to find the percentage increase in distance. It can be calculated as follows :
So, the increase in distance is equal to 24.61%.
Answer:
c=7.07
Step-by-step explanation:
c²=a²+b²
c²=5²+5²
c²=25+25
c²=50
c=√50
c=7.07
B. c=7.07 (to nearest hundredth)
C. c=√50= 5√2 in radical form
Answer:
Step-by-step explanation:
3 sheets are shared between four friends.
Each friends will get = 3 ÷ 4
=
Mrs. Benson has 184 math assignments left to grade.
<u>Step-by-step explanation:</u>
Here we have , Mrs. Benson has graded 46 math assignments but has 80% of the assignments left to grade.We need to find Mrs. Benson has how many math assignments left to grade. Let's find out:
Let total Number of math assignments be x , So According to question 46 math assignments are graded & 80% are left i.e.
⇒
⇒
⇒
⇒
⇒
⇒
Now , Assignments left to grade is :
⇒
⇒
Therefore , Mrs. Benson has 184 math assignments left to grade.