Name the property 2(2x-3)=4x-6
2 answers:
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Answer:
The value of the test statistic is z = -0.877.
Step-by-step explanation:
Testing the difference in mean time spent on housework between husbands and wives.
At the null hypothesis, we test if there is no difference, that is, the subtraction of the means is 0:
At the alternate hypothesis, we test if there is a difference, that is, the subtraction of the means is different from 0.
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis, and s is the standard error.
0 is tested at the null hypothesis:
This means that
For the wives the mean was 7 hours/week and for the husbands the mean was 4.5 hours/week. The standard deviation of the differences in time spent on house work was 2.85.
This means that
What is the value of the test statistic for testing the difference in mean time spent on housework between husbands and wives?
The value of the test statistic is z = -0.877.
Check the tree diagram of the problem:
The first ball can be either Red or Blue, the second ball can either be Red or Blue.
The branches represent all possible scenarios.
For example, consider the upper branch, the case when both balls are blue:
The first ball is Blue, probability 5/10, the second ball is Blue, probability 4/9 because now there are 4 left blue balls, and 9 balls in total, after we picked the first blue.
The other branches have the same logic.
The question is not completed so we have 2 cases:
"Find the probability that at least 1 ball was red, given that the first ball was red"
here we add the separate probabilities of (R, R) and (R, B)
P(R,R)+P(R,B)=2/9 + 5/18 = 4/18 +5/18= 9/18=0.5
"Find the probability that at least 1 ball was red, given that the first ball was blue"
probability is P(B, R)=5/18=0.28
The first ball can be either Red or Blue, the second ball can either be Red or Blue.
The branches represent all possible scenarios.
For example, consider the upper branch, the case when both balls are blue:
The first ball is Blue, probability 5/10, the second ball is Blue, probability 4/9 because now there are 4 left blue balls, and 9 balls in total, after we picked the first blue.
The other branches have the same logic.
The question is not completed so we have 2 cases:
"Find the probability that at least 1 ball was red, given that the first ball was red"
here we add the separate probabilities of (R, R) and (R, B)
P(R,R)+P(R,B)=2/9 + 5/18 = 4/18 +5/18= 9/18=0.5
"Find the probability that at least 1 ball was red, given that the first ball was blue"
probability is P(B, R)=5/18=0.28