Answer:
KE = 1/2mv^2
KE = 1/2(24)(3^2)
KE = 12(9)
KE = 108 J
Let me know if this helps!
Answer: F = 3.28 × 10^-7 N
Explanation:
Alpha particle charge (q)= 2e
e = 1.6 × 10^-19
q = 2e = 2 × (1.6 *10^-19) = 3.2 × 10^-19
1/4πEo = 9 × 10^9
Distance(r) = 5.3 × 10^-11m
The force of attraction between the two particles is given by:
F = (1/4πEo) (q1q2 / r^2)
F = [(9 × 10^9) (3.2 × 10^-19) (3.2 × 10^-19)] / (5.3 × 10^-11)^2
F = (92.16 × 10^(9 - 19 - 19)) / 28.09 × 10^-22
F = (92.16 × 10^-29) / 28.09 × 10^-22
F = 3.28 × 10^(-29 + 22)
F = 3.28 × 10^-7 N
I'll take the gravitational constant G to be 6.67x10^-11 in this. I will also be using the mass of the earth as 5.972x10^24 (there might be a way to solve this without knowing the mass of the Earth but it has escaped me, if anyone wants to help me out on this then feel free).
We can calculate the gravity of the earth at the distance above it using
g=mG/r^2
Substituting in, we get
g=(5.972x10^24)x(6.67x10^-11)/(6380000+8960000)^2
=1.69 to 3sf
We also know that w=mg, so the weight of the astronaut is w=76x1.69=128.44N = 128N to 3sf
The earth is revolving around the sun and when the seasons change the earth tilts at a different angle and it changes your perspective on the constellations<span />
Answer:
My favorate activies is skateboareding, and I prerfer outdoor actives.
Explanation: