Answer:
Explanation:
base of triangular frame, b = 90 cm
Area, A = 765 cm²
Let the height is h.
Area of a triangular frame = 1/2 x base x height
765 = 0.5 x 90 x h
h = 17 cm
Thus, the height of triangular frame is 17 cm.
A = (Vf-Vi) / t,
a = (6-0)/3 = 2m/s^2,
F = ma = 2 * 2 = 4N
Given:
Work done, W = 5 J
Initial energy = 8J
Final energy = 30J
Let's determine if the work done have a positive or nrgative value.
Appy the equation for the first lae of thermodynamics:
![\Delta U=Q-W](https://tex.z-dn.net/?f=%5CDelta%20U%3DQ-W)
Where:
U is the change in internal energy
Q is the added heat
W is the work done
To find the work done here, we have:
Rewrite the formula for W
![W=Q-\Delta U](https://tex.z-dn.net/?f=W%3DQ-%5CDelta%20U)
Where:
ΔU = 30J - 8J = 22J
Q = 5J
Thus, we have:
![\begin{gathered} W=5J-22J \\ \\ W=-17J \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20W%3D5J-22J%20%5C%5C%20%20%5C%5C%20W%3D-17J%20%5Cend%7Bgathered%7D)
Therefore, the work done here is -17J.
This means the work done in this scenario has a negative value.
ANSWER:
The work done in this scenario has a negative value