Please help its for science
2 answers:
You might be interested in
Answer:
Explanation:
In this case we will use the Bohr Atomic model.
We have that:
We can calculate the centripetal force using the coulomb formula that states:
Where K=
and r is the distance.
Now we can say:
The mass of the electron is = Kg
The charge magnitud of an electron and proton are=
Substituting what we have:
[/tex]
so:
The question is incomplete. The complete question is :
Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and exactly between them, you hear a minimum of intensity. As you walk parallel to the plane of the speakers, staying 3.0 m away, the sound intensity increases until reaching a maximum when you are directly in front of one of the speakers. The speed of sound in the room is 340 m/s.
What is the frequency of the sound?
Solution :
Given :
The distance between the two loud speakers,
The speaker are in phase and so the path difference is zero constructive interference occurs.
At the point , the speakers are out of phase and so the path difference is
Therefore,
Thus the frequency is :
Hz
Answer:
x(t) = 0.077cos(6.455t)
Explanation:
If the spring can be stretched 0.2 m by a force of 50 N, then the spring constant is:
k = 50 / 0.2 = 250 N/m
The equation of simple harmonic motion is as the following:
where
We also know that the initial velocity is 0.5 m/s, which is also the maximum speed at the equilibrium:
is the initial phase
Therefore, the position of the mass after t seconds is
x(t) = 0.077cos(6.455t)