Answer:
Let's start by understanding what exactly a scientific question is. A scientific question is a question that may lead to a hypothesis and help us in answering (or figuring out) the reason for some observation. A good scientific question has certain characteristics. It should have some answers (real answers), should be testable.
Here's examples of a few:
Why is that a star?
or
What is that star made of?
Hope this can lead you to the answer you're looking for at least!!
Answer:
The vector sum of all forces acting on it is zero, its at equilibrium.
Explanation:
The bag of marbles hanging on a spring scale applies its weight downwards, which was counterbalanced by the reaction from the spring scale (obeying the Newton's third law of motion). And since no external forces are applied to the system, thus the equilibrium of the system.
If the weight of the bag is greater than the reaction from the spring scale, the scale breaks and the system would not be balanced.
Since you are referring to the TI-203 and TI-205, you need to know the actual masses of these two isotopes. TI-203 has 202.9723 amu and TI-205 has 204.9744 amu. Since you are concluding that this Thallium have 29.5% (Ti-203) and 70.5% (Ti-205), you need to multiply the percentage to the actual masses of the isotopes. With that, you should be able to get 204.3833 amu
Answer:
Explanation:
at collision, m has a velocity of √2gR
The center of mass of the system has a velocity of
m(√2gR) + 3m(0) = (m + 3m)v
v = ¼√2gR
The stationary mass (3m) will depart at twice the system center of mass velocity
v(3m) = ½√2gR ANSWER B
The relative velocity before the collision will be the negative of the relative velocity after the collision.
v(m) = ½√2gR - √2gR = -½√2gh ANSWER A
m will rise to a height of v²/2g = (-½√2gR)²/2g = 0.25R
Explanation:
The acceleration due to gravity is on Earth is given by :
..............(1)
Where
M is the mass of Earth
R is the radius of Earth
G is the universal gravitational constant
The formula for acceleration due to gravity on planet is given by :
..............(2)
Since, 
From equation (1) and (2) :
So, the acceleration on the planet is 64 feet per second square. Hence, this is the required solution.
