Answer:
Ex(P) = -3.602 x 10^6 N/C
Explanation:
- q2 = 2.6 μC = the net charge on the conducting shell
- inner radius of conducting shell = a = 2.2 cm =0.022m
- outer radius of conducting shell = b = 4.5 cm = 0.045m
1) To get Ex(P), the value of the x-component of the electric field at point P, located a distance 8.8 cm along the x-axis from q1 ;
Ex(P) = k(q1+q2)/r^2
= 9 x 10^9 (-5.7 + 2.6) x 10^-6 /0.088^2
Ex(P) = -27.9 x 10^3/ 0.007744
Ex(P) = -3.602 x 10^6 N/C
Answer:
5900J
Explanation:
Work=Forse*Distance
work = J, Jewls
100*59=5900
Hop this helps and can u think about brainlist
i put a picture on how to find these answers, if u got any more questions im here
Answer:
a.) The main scale reading is 10.2cm
b.) Division 7 = 0.07
c.) 10.27 cm
d.) 10.31 cm
e.) 10.24 cm
Explanation:
The figure depicts a vernier caliper readings
a.) The main scale reading is 10.2 cm
The reading before the vernier scale
b.) Division 7 = 0.07
the point where the main scale and vernier scale meet
c.) The observed readings is
10.2 + 0.07 = 10.27 cm
d.) If the instrument has a positive zero error of 4 division
correct reading = 10.27 + 0.04 = 10.31cm
e.) If the instrument has a negative zero error of 3 division
correct reading = 10.27 - 0.03 = 10.24cm
Answer:
B
Explanation:
Reflect: (of a surface or body) throw back (heat, light, or sound) without absorbing it.
For this case we have the following equation:
h (t) = -16t ^ 2 + 36t + 36
By the time the rock hits the water we have:
-16t ^ 2 + 36t + 36 = 0
Solving the second degree polynomial we have:
t1 = -3/4
t2 = 3
We discard the negative root because we want to find the time.
Answer:
It will take for the rock to hit the water about:
t = 3 seconds