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2 years ago

What is 99,999 rounded to the nearest thousands

Mathematics

2 answers:

konstantin123 [22]2 years ago

5 0

100,000

is the answer

guapka [62]2 years ago

4 0

All you have to do is go to the thousands place and if the number is 5 or higher then raise the number by one in the thousands place, if it is under 5 then lower it in the thousands place!

~I hope this helped!

I am, yours most sincerely,
Joshua A. Bunn

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Its worth 25 please help and show work

melamori03 [73]

9514 1404 393

Answer:

3) y = √10

4) x = 5√2

Step-by-step explanation:

The side ratios of an isosceles right triangle (one of the "special" right triangles) are ...

1 : 1 : √2

So, for some multiplier k, they can be made to match the sides in your triangles.

3) 1·k : 1·k : k√2 = √5 : √5 : y

Clearly, k = √5, so ...

y = (√5)(√2)

y = √10

4) k : k : k√2 = x : x : 10

k = 10/√2 = (5√2)/2

k = x = (5√2)/2

5 0

2 years ago

(Refer to the attached image)

RSB [31]

Answer:

missing side: 133 cm

Explanation:

Provided 2 length sides and one angle also need to find one missing side.

So, use cosine rule:

⇒ a² = b² + c² - 2bc cos(A)

Insert values

⇒ g² = 166² + 147² - 2(166)(147) cos(50)

⇒ g² = 17794.3935

⇒ g = √17794.3935

⇒ g = 133.3956

⇒ g = 133 (rounded to nearest whole number)

8 0

1 year ago

Triangle MNO is an equilateral triangle with sides measuring 16 StartRoot 3 EndRoot units. Triangle M N O is an equilateral tria

Lesechka [4]

Answer:

The correct option is second one i.e 24 units.

Therefore the height of the triangle is

$NR=24\ units$

Step-by-step explanation:

Given:

An equilateral triangle has all sides equal.

ΔMNO is an Equilateral Triangle with sides measuring,

$NM = MO = ON =16\sqrt{3}$

NR is perpendicular bisector to MO such that

$MR=RO=\dfrac{MO}{2}=\dfrac{16\sqrt{3}}{2}=8\sqrt{3}$ .NR ⊥ Bisector.

To Find:

Height of the triangle = NR = ?

Solution :

Now we have a right angled triangle NRM at ∠R =90°,

So by applying Pythagoras theorem we get

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

Substituting the values we get

$(MN)^{2} = (MR)^{2}+(NR)^{2}\\\\(16\sqrt{3})^{2}=(8\sqrt{3})^{2}+(NR)^{2}\\\\(NR)^{2}=768-192=576\\Square\ rooting\ we\ get\\NR=\sqrt{576}=24\ units$