Answer:

Step-by-step explanation:
<u>GIVEN :-</u>
Amount of fabric required for :-
- a single window =

- a double window =

<u>TO FIND :-</u>
Amount of fabric required for two single windows and one double windows.
<u>SOLUTION :-</u>
Amount of fabric required for two single windows = 
Amount of fabric required for 2 single & 1 double window = 
= 
= 
= 
Just multiply each fraction by 100
a. is (6*100) /100 = 6 per cent
b = (3*100) / 8 = 37.5 %
do same for the last 2
The point halfway between the two cities would be the midpoint, which is found by averaging the x and y coordinates. In this case the point would be ((3+7)/2, (4+1)/2) = (5, 2.5). The distance between the stadium and the high school can be found using the distance formula and then multiplying by 10.9 miles. That would get us 10.9sqrt((7-3)^2+(4-1)^2) = 54.5 miles if I did that mental math right.
3) x² - 121 = 0
x² = 121
x' = +√121
x' = 11
_______________
x'' = - √121
x'' = -11
Solution ⇒ S{-11 ; 11 } or (x-11)(x+11)
4) 4x² + 144 = 0
4x² = -144
x² = -144 / 4
x² = -36
x = √-36
No solution ⇒ S = ∅
5) z²+10z+21 = 0
Δ = 10² - 4(1)(21)
Δ = 100 - 84
Δ = 16
x' = (-10+4) / 2 = -6/2 = -3
x'' = (-10-4) / 2 = -14/2 = -7
Solution ⇒ S{ -7 ; -3} or (x+3)(x+7)
7^2x4 = n^8
7^8 = n^8
n = 7