If you need the geometry and trigonometry I'll post those. Instead I found an answer at this link: http://jwilson.coe.uga.edu/EMAT6450/Class%20Projects/Scarpelli/Scarpelli_MathematicsBaseballActivity.....
The distance from home plate to the pitcher's mound is 60.5 feet and from home plate to second base is <span>127.28 feet.
Pitcher's Mound to 2nd base = </span><span>
<span>
<span>
66.78</span> </span>f</span>eet
Given those distances, we KNOW a 50 foot sprinkler will NOT reach home plate and second base from the pitcher's mound.
I didn't figure out the pitcher's mound to 1st or to 3rd, since the question is already answered.
A=p(1+i/m)^mn
A=980×(1+0.08÷4)^(4×5)
A=1,456.23
Looking at the graph you can see that the domain of the function is:
[0, 3.85]
To find the range of the function, we must follow the following steps:
Step 1)
Evaluate for t = 0
h (0) = - 4.87 (0) ^ 2 + 18.75 (0)
h (0) = 0
Step 2)
find the maximum of the function:
h (t) = - 4.87t ^ 2 + 18.75t
h '(t) = - 9.74 * t + 18.75
-9.74 * t + 18.75 = 0
t = 18.75 / 9.74
t = 1.925051335
We evaluate the function at its maximum point:
h (1.925051335) = - 4.87 * (1.925051335) ^ 2 + 18.75 * (1.925051335)
h (1.93) = 18.05
The range of the function is:
[0, 18.05]
Answer:
Domain: [0, 3.85]
Range: [0, 18.05]
option 1
