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Savatey [412]
3 years ago
7

Factor: (a+3)^2 -a(a+3)

Mathematics
2 answers:
lutik1710 [3]3 years ago
6 0

Answer:

3(a +3)

Step-by-step explanation:

(a+3)^2 -a(a+3)

FOIL

a^2 +3a+3a+9 -a(a+3)

Distribute

a^2 +3a +3a +9 -a^2 -3a

Combine like terms

3a +9

FACTOR out a+3

(a+3)( a+3 -a)

(a+3) (3)

3(a+3)

Andru [333]3 years ago
4 0

Answer:

3(a+3)

Step-by-step explanation:

Expand the first set of brackets first

(a+3)^2

A^2 + 3a + 3a +9

=A^2 + 6a + 9

Expand the second set of brackets

-a(a+3)

=-a^2 - 3a

Add both sets together

3a + 9

Factorise:

3(a+3)

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Step-by-step explanation:

1 Remove parentheses.

8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}

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3 Take out the constants.

\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

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\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

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-16{y}^{8}{x}^{3}

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