Problem 1
With limits, you are looking to see what happens when x gets closer to some value. For example, as x gets closer to x = 2 (from the left and right side), then y is getting closer and closer to y = 1/2. Therefore the limiting value is 1/2
Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)
Use examples like this and you'll get the results you see in "figure 1"
For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.
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Problem 2
This is basically an extension of problem 1. The same idea applies. See "figure 2" (in the attached images) for the answers.
First we would change the fractions into decimals and compare them. That way it would be easy to solve when needed.
1/2=0.50
5/8=0.625
1/8=0.125
Now we can see that 1/8 (0.125) is the smallest, followed by 1/2 (0.50), and 5/8 the largest. Now we can match the sizes with the insects.
Since the tiger beetle is the largest we will place that with the length of 5/8 since that is the largest.
The carpenter ant is second largest so it would be matched with 1/2
The aphid is the smallest so that would be with 1/8 as the smallest
*Hope that helped :D*
Answer:
Area of sector = 102.6 feet squared
Step-by-step explanation:
Given:
Radius of circle = 14 ft
Angle θ = 60°
Find:
Area of sector
Computation:
Area of sector = [θ/360]πr²
Area of sector = [60/360](22/7)(14)²
Area of sector = [1/6][22/7][196]
Area of sector = 102.6 feet squared
Given,
Rate of free fall = 216 km/h
Solution,
km/h to m/s is converted as follows :

So, the rate of fall is 60 m/s.
If t = 20 s
Assume, initial velocity = 0
It will move under the action of gravity.
Using equation of motion,

Hence, this is all for the solution.
The percent of time the photographer spent negotiating with the bison greater than the time he spent taking pictures is 500%
<h3>Percentage</h3>
- Time spent taking pictures = 5 minutes
- Time spent negotiating = 30 minutes
Percentage of time negotiating greater than taking pictures = (difference in time) / time to take pictures × 100
= (30 - 5) / 5 × 100
= 25/5 × 100
= 5 × 100
= 500%
Learn more about percentage:
brainly.com/question/843074
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