How high is a tree that casts a 33 ft shadow at the same time a 5 ft pole casts a shadow which is 12 ft long?
let x=height of the tree
x/33=5/12
x=5*33/12
x=13.75
Answer:
B
Step-by-step explanation:
Answer:
the answer is A.
Step-by-step explanation:
when you move 3 back you go in to ones, tens, hundreds, and thousands. to simply get back just mutiplye by 1,000
x= -4 and x=8
f(x) =6║x-2║+3
39= 6║x-2║+3
36=6║x-2║
6=║x-2║
-(x-2)=6
-x+2=6
x=-4
x-2=6
x=8
4x10^-3 is another way to represent 3^-5
