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Mrrafil [7]
2 years ago
8

What is 5/6 × 4/9? I'm a little confused

Mathematics
1 answer:
forsale [732]2 years ago
6 0

Answer:

10/27

Step-by-step explanation:

5/6 * 4/9 = 20/ 54 = 10/27

You might be interested in
Line segment TV is a midsegment of ∆QRS. What is the value of n in the triangle pictured?
Elis [28]

Answer:

D. 3.2

Step-by-step explanation:

Mid-segment Theorem of a triangle states that the Mid-segment in a triangle is half of the third side of the triangle.

Based on this theorem, we have: TV = ½(RS)

TV = 3n - 2

RS = n + 12

Substitute

3n - 2 = ½(n + 12)

Multiply both sides by 2

2(3n - 2) = (n + 12)

6n - 4 = n + 12

Collect like terms

6n - n = 4 + 12

5n = 16

Divide both sides by 5

5n/5 = 16/5

n = 3.2

4 0
3 years ago
Vidriana rolled a number cube 96 times. Her results are shown in the table, what is the experimental probability of rolling an e
hichkok12 [17]

Answer:

50/96

Step-by-step explanation:

I assume the table is:

\left[\begin{array}{cc}Result&Total\\1&15\\2&13\\3&16\\4&17\\5&15\\6&20\end{array}\right]

Even numbers are 2, 4, and 6.  The total number of times she rolled an even number is 13 + 17 + 20 = 50.

So the probability is 50/96.

7 0
3 years ago
Given an acceleration vector, initial velocity u0,v0,w0 , and initial position x0,y0,z0 , find the velocity and position vectors
dsp73

Answer:

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

Step-by-step explanation:

given that acceleration vector is a funciton of time and at time t

a(t) = (5,5t, 8t)

v(t) can be obtained by integrating a(t)

v(t) = (5t, 5t^2/2, 4t^2)+(u_0,v_0,w_0)\\=(5t+15, 5t^2/2, 4t^2)

Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.

The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)

Position vector can be obtained by integrating v(t)

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

5 0
3 years ago
BRAINLIEST FOR CORRECT ANSWER!!!
aleksklad [387]

Answer:

B?

Step-by-step explanation:

3 0
3 years ago
Fill in the blanks.
Anna [14]

Answer:

In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.7 percent are within 3 standard deviations of the mean.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Also:

The normal distribution is symmetric, which means that 50% of the data is above the mean and 50% is below.

Then:

In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.7 percent are within 3 standard deviations of the mean.

4 0
3 years ago
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