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saw5 [17]
3 years ago
12

PLEASEEEEEEEEEEEEEEEEEEEEEEEEE HELP MEEEEEEEEEEEEEEEEEEEEEEEE

Mathematics
2 answers:
Gnom [1K]3 years ago
6 0

Answer:

C = 14 x Pi

C = 14 x 3.14

C = 43.96 in

wolverine [178]3 years ago
5 0

Answer:

Step-by-step explanation:

The answer to (A) is N/A and the answer to (B) is N/A again (Hope this helps!)

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There are 4 boxes of cookies each box holds 8 cookies how many childrrn can be served 2 cookies each
REY [17]
The answer would be 16.
 

you have to multiply 4 and 8 which =32 and then divide 32 by 2 which =16
6 0
3 years ago
Read 2 more answers
Find an equation of the tangent line to the curve 2(x2+y2)2=25(x2−y2) (a lemniscate) at the point (−3,1). An equation of the tan
valina [46]

2(x^2+y^2)^2=25(x^2-y^2)

Let y=y(x), so that differentiating both sides wrt x gives

4(x^2+y^2)\left(2x+2y\dfrac{\mathrm dy}{\mathrm dx}\right)=25\left(2x-2y\dfrac{\mathrm dy}{\mathrm dx}\right)

If x=-3 and y=1, the above reduces to

40\left(-6+2\dfrac{\mathrm dy}{\mathrm dx}\right)=25\left(-6-2\dfrac{\mathrm dy}{\mathrm dx}\right)\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac9{13}

This is the slope of the tangent line, which has equation

y-1=\dfrac9{13}(x+3)\implies\boxed{y=\dfrac{9x+40}{13}}

7 0
2 years ago
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
2 years ago
What is another name for line m?
Ganezh [65]
I’m pretty sure it’s the slope
5 0
3 years ago
Which expressions are equivalent to -2.5(1-2n) - 1.5n
Keith_Richards [23]

Answer:

-5n - 4


Step-by-step explanation:

The goal is to simplify this expression.


1. Distribute

-2.5 * 1 = -2.5

-2.5 * 2n = -5n


Now, we have

-2.5 - 5n - 1.5


2. Combine like terms

-2.5 + (-1.5) = -4 (+ * - = -   The - cancels out the +)


3. Put it together

-5n - 4


I hope I helped!

Let me know if you need anything else!

~ Zoe



4 0
3 years ago
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