Evaluate b^2c^-1 for b=8 and c=-4

1 answer:

4 0

When evaluating b^2c^-1 for b=8 and c=4, the answer is -16

E = b^2c–1
x-a = 1/xa

E = b^2c - 1
= 8^2 x (-4)-1
= 64/-4
= -16

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A sample of 36 observations is selected from one population with a population standard deviation of 4.2. The sample mean is 101.

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Answer:

Step-by-step explanation:

Given that :

the null and the alternative hypothesis are computed as :

$H_o: \mu_1 = \mu_2$

$H_a : \mu _1 \neq \mu_2$

This is a two tailed test

This is because of the ≠ sign in the alternative hypothesis which signifies that the rejection region in the alternative hypothesis are at the both sides of the hypothesized mean difference .

Decision Rule: at the level of significance ∝ = 0 . 10

The decision rule is to reject the null hypothesis if z < - 1 . 64 and z > 1 . 64

NOTE: DURING THE MOMENT OF TYPING THIS ANSWER THERE IS A TECHNICAL ISSUE WHICH MAKES ME TO BE UNABLE TO SUBMIT THE FULL ANSWER BUT I'VE MADE SCREENSHOTS OF THEM AND THEY CAN BE FOUND IN THE ATTACHED FILE BELOW