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laila [671]
3 years ago
13

the first term of an arithmetic sequence is 2 and the sum of the first 15 terms is 292.5. Find the common difference

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0

Given:

First term of an arithmetic sequence is 2.

Sum of first 15 terms = 292.5

To find:

The common difference.

Solution:

We have,

First term: a=2

Sum of first 15 terms: S_{15}=292.5

The formula of sum of first n terms of an AP is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Where, a is first term and d is common difference.

Putting S_{15}=292.5, n=15 and a=2 in the above formula, we get

292.5=\dfrac{15}{2}[2(2)+(15-1)d]

292.5=\dfrac{15}{2}[4+14d]

292.5=15[2+7d]

Divide both sides by 15.

\dfrac{292.5}{15}=2+7d

19.5=2+7d

19.5-2=7d

17.5=7d

Dividing both sides by 7, we get

\dfrac{17.5}{7}=d

2.5=d

Therefore, the common difference is 2.5.

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Domain of a function

We want to find the domain of the following function:

=ln\mleft(^2-6-55\mright)

This means that we want to find the x-values that it can take.

<h2>STEP 1: analyzing the simplies form of the function</h2>

Let's analyze the simpliest form of the function:

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Its graph is:

Then, for the simpliest form of the function, the x-values can only be higher than 0.

This means that its domain is

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<h2>STEP 2: domain of the given function</h2>

Based on the above we can deduce that for the <em>ln(x)</em> function, what is inside the parenthesis should be higher than 0 on this kind of functions.

This is that for

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then

^2-6-55>0<h2>STEP 3: finding the x values that make x²-6x-55>0 (factoring)</h2>

In order to find the values of x that make

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we must factor it.

We want to find a pair of numbers that when multiplied give the last term (-55) and when added together give the second term (-6).

For the last term of the polynomial: -55, we have that

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The pair of numbers that when multiplied give the last term (-55) and when added together give the second term (-6), are: 5 and -11

We use them to factor the polynomial:

^2-6-55=(x+5)(x-11)

Then,

(x+5)(x-11)>0<h2>STEP 4: finding the x values that make (x+5)(x-11)>0 (factoring)</h2>

In order to find them, we are going to separate the factors (x+5) and (x-11) and analyze when they are positive or negative:

Combining them:

Since we are going to multiply both factors:

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We use the diagram to analyze the sign of their product:

Then

(x+5)(x-11)>0

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Therefore, expressed in set notation:

domain = {x|x∈(-∞, -5)∪(11, ∞)}

<h2>Answer: domain = {x | x ∈ (-∞, -5)∪(11, ∞)}</h2>

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