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konstantin123 [22]
3 years ago
8

Violet buys a premium sound system that is on sale for 40% off the original price. The original price is $224 more than the sale

price
Mathematics
1 answer:
Firdavs [7]3 years ago
7 0

Answer:

The original price was of $560, while the sales price was of 560 - 224 = $336.

Step-by-step explanation:

Original price:

x

Sales price:

224 less than the sales price, that is:

x - 224.

On sale fo 40% of the original price:

So the sales price is 100 - 40 = 60% = 0.6 of the original price. That means that:

x - 224 = 0.6x

0.4x = 224

x = \frac{224}{0.4}

x = 560

The original price was of $560, while the sales price was of 560 - 224 = $336.

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<em>It's (C) -7 + 5i.</em>

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Bill Board is "lording" his SAT score over his friend, Rhoda Dendron, who took the ACT. "You only got a 25 in math," he chortled
SCORPION-xisa [38]

Answer:

Rhoda, whose ACT has a z-score of 1, scored in the 84th percentile in the ACT, compared to Bill, whose SAT has a z-score of -2, who scored in the 2nd percentile on the SAT. Due to the higher percentile(higher z-score)  on her test, Rhoda did better on her respective test than Bill, and thus, his logic is wrong.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Bill:

Scored 300, so X = 300

SAT has a μ of 500 and a σ of 100.

His z-score is:

Z = \frac{X - \mu}{\sigma}

Z = \frac{300 - 500}{100}

Z = -2

Z = -2 has a p-value of 0.02.

This means that Bill, whose SAT score has Z = -2, scored in the 2nd percentile.

Rhoda

Scored 25, so X = 25.

ACT has a μ of 20 and a σ of 5

Her z-score:

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 20}{5}

Z = 1

Z = 1 has a p-value of 0.84

This means that Rhoda, whose ACT score has Z = 1, scored in the 84th percentile.

What is wrong with Bill’s logic ?

Rhoda, whose ACT has a z-score of 1, scored in the 84th percentile in the ACT, compared to Bill, whose SAT has a z-score of -2, who scored in the 2nd percentile on the SAT. Due to the higher percentile(higher z-score)  on her test, Rhoda did better on her respective test than Bill, and thus, his logic is wrong.

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3 years ago
I need help I’m not sure
Daniel [21]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad  (\stackrel{x_2}{-6}~,~\stackrel{y_2}{-6}) \qquad \left(\cfrac{ x_2 +  x_1}{2}~~~ ,~~~ \cfrac{ y_2 +  y_1}{2} \right) \\\\\\ \left( \cfrac{-6+3}{2}~~,~~\cfrac{-6+5}{2} \right)\implies \left(\cfrac{-3}{2}~~,~~\cfrac{-1}{2}  \right)\implies \left( -1\frac{1}{2}~,~-\frac{1}{2} \right)

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3 years ago
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