The code is 200 because they went under the sea to get the key to work.
Answer:
Step-by-step explanation:
I used calculus for this, as I'm not sure there's any other way to do it and to do it as easily. This is the volume of a solid found by using the disk method of rotation:
![V=\pi\int\limits^a_b {[R(x)]^2-[r(x)]^2} \, dx](https://tex.z-dn.net/?f=V%3D%5Cpi%5Cint%5Climits%5Ea_b%20%7B%5BR%28x%29%5D%5E2-%5Br%28x%29%5D%5E2%7D%20%5C%2C%20dx)
where R(x) is the outer shell of the solid and r(x) is the space inbetween the solid and the axis of rotation. There is no space between the solid and the axis of rotation, so r(x) = 0. R(x) is the height of the solid which is 3. Therefore, f(x) = 3 and that's the function we put into the formula with the lower bound of 3 and the upper bound of 5:
and
and integrating:
and using the First Fundamental Theorem of Calculus:
V = π(9(5) - 9(3)) and
V = π(45 - 27) so
V = 18π units cubed or in decimal format,
V = 56.549 units cubed
Answer: 26
Step-by-step explanation: you divide 468 and 18 and you get 26.
I am not sure but I did this in my head and then I did it on the calculator and it was 20
The average rate of change over some interval [a, b] is equal to the slope of the secant line from (a, h(a)) to (b, h(b)).
h(t) is a quadratic function, so its graph is a parabola, and in particular it's one that has a minimum of -4 when t = 2.
The secant line over an interval [a, b] will have a negative slope if the distance from a to 2 is larger than the distance from b to 2.
(A) If a = 4 and b = 5, then |a - 2| = 2 and |b - 2| = 3, so the slope and hence average rate of change is positive.
(B) If a = -1 and b = 5, then |a - 2| = 3 and |b - 2| = 3, so this ARoC is zero.
(C) If a = 0 and b = 4, then |a - 2| = 2 and |b - 2| = 2, so this ARoC is also zero.
(D) If a = -1 and b = 4, then |a - 2| = 3 and |b - 2| = 2, so this ARoC is negative.
