Answer: 0
Step-by-step explanation:
[24 - (15 + 2) +3] -9
[24-(17) +3] -9
[7 +3] -9
9 - 9 = 0
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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The value of cos B is 12/13
Try 1(18) / 2
Just multiply 1 by 18 and divide 18 by 2.
Then we have 9!
