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zimovet [89]
2 years ago
15

How do the ratios of lengths, areas, and volumes compare in similar solids?

Mathematics
1 answer:
kondor19780726 [428]2 years ago
7 0

If the ratio between the sides is r, the ratio between the areas will be r^2 and the ratio between the volumes will be r^3

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Let f(x)= x^2-4x-c. Find a nonzero value of c such that f(c)=c.​
Dimas [21]

Answer:

The nonzero value of c will be:

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Step-by-step explanation:

Given the function

f\left(x\right)=\:x^2-4x-c

f\left(c\right)=\:c^2-4c-c

as

f(c) = c

so

c=\:c^2-4c-c

switching the sides

c^2-4c-c=c

subtract c from both sides

c^2-4c-c-c=c-c

c^2-6c=0

c\left(c-6\right)=0

Using the zero factor principle

\:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

c=0\quad \mathrm{or}\quad \:c-6=0

so, the solutions to the quadratic equations are:

c=0,\:c=6

Therefore, a nonzero value of c will be:

  • c = 6
5 0
2 years ago
From 5miles to 16miles
vfiekz [6]
From 5 miles to 16 miles in 11 miles in between.
3 0
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Reika [66]

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2 years ago
The area of a rectangular gymnasium is (5x+5x) square feet. If it is 5x feet wide, what is the length, in feet?
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

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    L = Area/W

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       =  5x( 1 + 1) / 5x

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5 0
2 years ago
If YC = 4, BC = 6, XY = 5, then AB =
Fittoniya [83]
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