Answer:
I believe the answer is 88ft^3 because I took 176 and divide by 2 to get 88ft^3 because I flip 1/2 to2/1.
Half of 36 is 18 so if 18+18=36
2
18
The joint variation that is given in the problem above can be expressed as follows:
w = k/d²
where w is the weight, k is the variation constant, and d is the distance from the center of the earth. Substituting the first scenario to obtain the value of k,
160 = k/(4000)²
k = 2.56 x 10^9
Using this value for the second scenario,
w = (2.56 x 10^9) / (8,000)² = 40 lbs
Thus, the weight of the man, 8000 miles above the center of the earth is 40 lbs.
Answer:
x = -2
Step-by-step explanation:
<h3>Given:</h3>
<h3>Note that:</h3>
<h3>
To find:</h3>
The circumference of the circular playing field.
<h3>Solution:</h3>
We'll have to multiply 2, π and radius.
Substitute the values according to the formula.
<u>Therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>circumference</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>circular</u><u> </u><u>playing</u><u> </u><u>field</u><u> </u><u>is</u><u> </u><u>47.12</u><u> </u><u>feets</u><u>.</u>
