Question

For what value of a does (1/9)^a+1 =81^a+1 x 27^2-a ?-4-226

Answer 1

Answer:

- 4

Step-by-step explanation:

Using the rule of exponents

• $a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

• $a^{-m}$ ⇔ $\frac{1}{a^{m} }$

$(\frac{1}{9}) ^{a+1}$ = $9^{-(a+1)}$ = $3^{-2(a+1)}$

and right side

= $3^{4(a+1)}$ × $3^{3(2-a)}$

Hence

$3^{-2a-2}$ = $3^{4a+4}$ × $3^{6-3a}$

$3^{-2a-2}$ = $3^{a+10}$

Equating exponents on both sides gives

a + 10 = - 2a - 2 ( add 2a to both sides )

3a + 10 = - 2 (subtract 10 from both sides )

3a = - 12 ( divide both sides by 3 )

a = - 4

Answer 2

Answer:

the answer to the question you is A on edg

Step-by-step explanation: