Answer:
a) 2048
b)164
c)54
d) 11
Step-by-step explanation:
a) A coin has two faces.
Outcome possible =2^11= 2048
b) 8 heads possible outcome = 11!/8!3! = 3971688/241/920= 164 ways
c)2 heads outcome= 11!/2!8!= 39716800/725760=54
d) 7 heads= 11!/7!6! =39716800/3628800 = 11
Answer:
The answer would be 31,737 elks.
Step-by-step explanation:
You would solve this by multiplying 1.08 by the power of 6 which equals 1.586874322944. You would then multiply this number by 20,000 which equals 31,737.4865 but since you can’t have .4865 of an elk the answer is just 31,737.
I hope this helps
There are infinite equivalent fraction can be obtained just multiple by any number to both numerator and denominator and you will find equivalent fraction !
as 42/16, 63/24 etc
<h3>
Answer: 8/25</h3>
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Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
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The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
