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3 years ago

What is the median of the data set? 87, 98, 106, 82, 111, 120

Mathematics

1 answer:

Contact [7]3 years ago

7 0

Answer:

The median is 102

Step-by-step explanation:

Median = a measure of central tendency. It represents the value for which 50% of observations a lower and 50% are higher. Put simply, it is the value at the center of the sorted observations.

Therefore, the answer 102 is correct.

(I need to be granted one more brainliest to level up so if my answer helped, it would be very much appreciated to award that to me, no obligations though!)

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What is greater 10 5/9 or 10.57

Romashka [77]

Answer:

10.57 is the greater number beacuse 5 divided by nine is 0.5 repeating

Step-by-step explanation:

then just round it to the nearest hundreth

GIVE ME BRAINLIEST AND HAVE A NICE DAY!

7 0

3 years ago

Please help lol LOL lol

Arte-miy333 [17]

<h2>Answer:</h2>

Step 1: 17 - 9 = 8

Step 2: 8 + 4 = 12

4 more girls came to the park

Hope this helps!!

<h2>- Carmelle -</h2>

7 0

2 years ago

Read 2 more answers

Simplify fully please

neonofarm [45]

Answer:

8x² + 8

Step-by-step explanation:

Given

(x² + 3)² - (x² - 1)² ← expand both factors using FOIL

= $x^{4}$ + 6x² + 9 - ( $x^{4}$ - 2x² + 1) ← distribute by - 1

= $x^{4}$ + 6x² + 9 - $x^{4}$ + 2x² - 1 ← collect like terms

= 8x² + 8

8 0

3 years ago

Read 2 more answers

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :