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Vesnalui [34]
3 years ago
11

Blaise’s school is selling tickets to a fall musical. On the first day of ticket sales they sold 8 adult tickets and 3 student t

ickets for a total of $79. On the second day they sold 10 adult tickets and 5 student tickets for a total of $105.
A.) Write a system of two equations to represent this scenario.

B.) What is the price per ticket for adults and children? Solve algebraically not by plugging numbers in.
Mathematics
1 answer:
dezoksy [38]3 years ago
4 0
Your two systems will be

8A + 3S = 79$

your 2nd will be

10A + 5S = 105$
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A balloon rises vertically at the rate
vodomira [7]

Answer:

a) 63°

b) 600ft

Step-by-step explanation:

To solve the above question, we would be using Trigonometric function

a) Find (to the nearest whole degree)

the angle with the horizontal at

which the balloon rises.

This above question a is a right angled triangle that is solved for using Trigonometric function of tan

From the question, we told that,

Vertical distance ( opposite side) = 10 feet

Horizontal distance ( adjacent side) = 5 feet.

Tan θ = opposite side/ adjacent side

Tan θ = 10/5

Tan θ = 2

θ = arc tan (2) or tan -¹(2)

θ = 63.434948823°

θ = 63°

The angle with the horizontal at

which the balloon rises to the nearest whole degree is 63°

b) find (to the nearest 10 feet) its

distance from the starting point

after one minute.​

Distance = Speed × time

Time is given in the question as 1 minute

We would convert it to seconds = 60 seconds

We are told in the question that the balloon rises vertically at the speed of 10ft/s

Distance = 10ft/s × 60seconds

Distance from the starting point per minute = 600ft

5 0
3 years ago
Question A: Suppose n - 15 is a whole number. What do you know
larisa [96]

Answer:

Question A: The value of n is positive.

Question B: n-17=64

Step-by-step explanation:

8 0
4 years ago
Please help I don't know what I'm doing wrong :/
vazorg [7]
You need to find the area of a kite in which case you would solve A=(pq)/2

P=16.3+16.3=32.6
Q=22.5+42.7
So pq=2,125.52
So A=1,062.76

So the answer is B
5 0
4 years ago
The following integral requires a preliminary step such as long division or a change of variables before using the method of par
shtirl [24]

Division yields

\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}

Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that

\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}

\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a

which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then

\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}

Now, in the integral we get

\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx

The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get

\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}

7 0
3 years ago
WILL GIVE BRAINLIEST!!!!!!
Tomtit [17]

Answer:

i really don't know but have a great day

Step-by-step explanation:

7 0
2 years ago
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