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3 years ago

5.

Mathematics

2 answers:

exis [7]3 years ago

6 0

33,155.22 is the correct answer for this

Paha777 [63]3 years ago

4 0

33,155.22 is the correct answer for this

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Two angles are complements if their sum is 90 degrees. The measure of one angle is one third the measure of its complement. Find

zysi [14]

Answer:

22.5 degrees

Step-by-step explanation:

90 = x + 3x

90 = 4x (divide by 4)

22.5 = x

22.5 + 67.5 = 90

5 0

3 years ago

Drag each expression to the correct location on the model. Not all will be used

grandymaker [24]

Answer: $\dfrac{x^{2}+2x+1 }{\mathbf {x-1}} \cdot \dfrac{\mathbf {5x^{2} +15x-20} }{7x^{2} +7x}$

Step-by-step explanation:

$\dfrac{\dfrac{5x^{2} +25x+20}{7x} }{\dfrac{x^{2} +2x+1}{7x^{2} +7x} } =\dfrac{5x^{2} +25x+20}{7x} \times \dfrac{7x^{2} +7x}{x^{2} +2x+1}=\dfrac{5x^{2} +25x+20}{7x} \times \dfrac{7x(x +1)}{(x+1)^{2} }=\\\\=\dfrac{5x^{2} +25x+20}{x+1} =\dfrac{{5(x+1)(x+4)}}{x+1}=5(x+4)$

$5(x+4)=\dfrac{5(x-1) \cdot (x+4)}{x-1}=\dfrac{5x^{2} +15x-20}{x-1}$

Thus, the expressions will be used: (5x² + 15x - 20) and (x + 4).

Let's check:

$\dfrac{x^{2}+2x+1 }{\mathbf {x-1}} \cdot \dfrac{\mathbf {5x^{2} +15x-20} }{7x^{2} +7x} =\dfrac{(x+1)^{2} }{x-1} \cdot \dfrac{5(x-1) \cdot (x+4)}{7x(x+1)} =\\\\=\dfrac{(x+1) \cdot 5 \cdot (x+4)}{7x} =\dfrac{5x^{2} +25x+20}{7x}$

5 0

3 years ago

ASAP PLEASEwrite an equation for the line that is parallel to tue given line and that passes through the given point. y=-5x+3; (

max2010maxim [7]

Answer:

$y=-5x-27$

Step-by-step explanation:

Since we are finding a parallel line, the slopes will be the same, so the second equation will also have a slope of -5.

Then, to find the y-intercept, we can use the point given and plug in.

$y=-5x+b$

$3=-5(-6)+b$

$3=b+30$

$b=-27$

So the equation comes out to be $y=-5x-27$

We can check by plugging in the given point again.

$3=-5(-6)-27$

$3=30-27$

$3=3$

7 0

4 years ago

Cost I-cost I-cost I cost = 4 cost cact verify

Makovka662 [10]

The answer is 4 cost cact because we see we have 4 items labeled cost so when we add them all up together as if they were variables we get 4.

7 0

3 years ago

Read 2 more answers

Let $f(x) = 2x + 7$ and $g(x) = 3x + c$. find $c$ if $(f \circ g)(x) = (g \circ f)(x)$ for all $x$.

boyakko [2]

Let me just rewrite the details in a more understandable manner

f(x) = 2x + 7
g(x) = 3x + c
f( g(x) ) = g( f(x) )

Proceeding to the problem, we have to find the value of c by making use of the relationship written by the third equation. The notation f( g(x) ) means that you have to replace x with g(x). So, you would have incorporate one equation to the other, and vice versa. By equating them, we can determine x. Let us start with f( g(x) ) .

f( g(x) ) = 2(3x + c) + 7
f( g(x) ) = 6x + 2c + 7

Next, we do the similar thing to g( f(x) ).
g( f(x) ) = 3(2x+7) + c
g( f(x) ) = 6x + 21 + c

Then, we equate both simplified equations
6x + 2c + 7 = 6x + 21 + c

Let's simplify further by placing c on one side, and the rest on the other side:
2c - c = 6x - 6x + 21 - 7
c = 14

5 0

4 years ago