Sum of 2 angles = 80°
Difference = 20°
If we take away 20° from the sum, both angles are equal
⇒80 - 20 = 60°
Divide by 2 to find the smaller angle:
60 ÷ 2 = 30
Add 20° to find the bigger angle:
20 + 30 = 50°
<u>One of the angle is 30° and the other angle is 50°</u>
Given that the sum of the two angles is 80°
⇒ Third angle = 180 - 80 = 100°
Answer: The 3 angles are 30° , 50° and 100°
Answer:
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Step-by-step explanation:
Here n= 20
Sample mean GPA = x`= 2.84
Standard mean GPA = u= 2.55
Standard deviation = s= 0.45.
Level of Significance.= ∝ = 0.01
The hypothesis are formulated as
H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students
against the claim
Ha: u1≠u2
i.e the GPA of night students is different from the mea GPA of day students
For two tailed test the critical value is z ≥ z∝/2= ± 2.58
The test statistic
Z= x`-u/s/√n
z= 2.84-2.55/0.45/√20
z= 0.1441
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
The volume formula of a cylinder is :
From the problem, the volume is 1 m^3 and the height is 0.6 m.
Substitute the given to the formula :
Take the square root of both sides of the equation :
![\begin{gathered} r^2=0.53 \\ r=\sqrt[]{0.53} \\ r=0.728 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%5E2%3D0.53%20%5C%5C%20r%3D%5Csqrt%5B%5D%7B0.53%7D%20%5C%5C%20r%3D0.728%20%5Cend%7Bgathered%7D)
The answer is r = 0.728 m
