Answer: 8359
Step-by-step explanation:
The formula for sample size needed for interval estimate of population proportion :-

Given : The significance level : 
Critical value : 
Previous estimate of proportion : 
Margin of error : 
Now, the required sample size will be :-

Hence, the required sample size = 8359
Answer:
41
Step-by-step explanation:
yellow marbles=5+ 3r(r is the number of red marbles)
red marbles=3r
3r+3r+5=77
6r=77-5
6r=72
r=72/6=12
yellow marbles = 5 + 3r
5+ 12 x 3
5+ 36
=41
The best way to compare fractions would be to make them have like
denominators. We first , in this case, need to convert from decimal to
fraction.
Converting decimals to fractions first requires an
understanding of the decimal places that fall after the decimal. One
place after the decimal is the tenths place. If you have a decimal that
ends at one place after the decimal (or in the tenths place) it can be
written as the number after the decimal in the top of the fraction and
ten (tenths place) in the denominator. ex. .5 ends one place after
the decimal and can be written as 5/10...(read as five tenths).
If a decimal ends at two places after the decimal...(ex. .75)...it
ends in the hundredths place, can be written as that number in the
numerator and 100 in the denominator....(ex 75/100) and is read as
seventy-five hundredths.
one place after the decimal is tenths (over 10), two places is
hundredths (over 100), three places is thousandths (over 1000) , four
places ten-thousandths (over 10000) and so on.
Because each decimal in your problem has a different amount of
decimal places, it makes for different denominators. But, We can add a
zero to the end of a decimal without changing it's value; if we add a
zero to the end of .5 and make it .50 , we then can write it as 50/100
and would now have like denominators.
if .5 = .50 = 50/100 and .75 = 75/100
we now have the question what fractions can fall between 50/100 and 75/100.
That would be fractions such as 51/100, 52/100, 53/100.......74/100.
Answer: -3.75
Step-by-step explanation:
10000000000% sure because I took the test
The solution to the given differential equation is yp=−14xcos(2x)
The characteristic equation for this differential equation is:
P(s)=s2+4
The roots of the characteristic equation are:
s=±2i
Therefore, the homogeneous solution is:
yh=c1sin(2x)+c2cos(2x)
Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:
yp=Axsin(2x)+Bxcos(2x)
If you take the second derivative of the equation above for yp , and then substitute that result, y′′p , along with equation for yp above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side, sin(2x) , you will find:
A=0
B=−14
Therefore,
yp=−14xcos(2x)
For more information about differential equation, visit
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