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Illusion [34]
3 years ago
5

Plz help me with this

Mathematics
1 answer:
aleksandrvk [35]3 years ago
7 0

Answer: b) -5 ≤ y ≤ 1

<u>Step-by-step explanation:</u>

y = 3 cos (4x) - 2

     ↓                 ↓

amplitude       vertical shift

The amplitude is 3 which gives a range of -3 to 3 but there is also a shift down of 2 units so the new range is: <u>-3 - 2 =</u> -5 to <u>3 - 2 =</u> 1

-5 ≤ y ≤ 1

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Which of the following is an equation of a line parallel to the equation y=4x+1?
Reil [10]

Answer:

y = 4x + b, where b is any number

Step-by-step explanation:

Adrian, you need to share the possible answer choices.

Every line parallel to y = 4x + 1 has the slope 4.

This is true for any y-intercept, that is, for any b in y = mx + b.

3 0
3 years ago
A chemist has a 30% and a 45% acid solution. What amount of each solution should be used to make 500ml of solution with 35% acid
9966 [12]
Not sure is this is right but if the chemist wants to make the solution 35% acidic then he can use all of the 30% acid and 5% of the 45% acid.
4 0
3 years ago
What is the coordinate of point P on the line segment AB that is 3/4 of the distance from A to B for A(2,5) and B(6,9)?
Brut [27]

Answer:

p  is (3.71, 6.71)

Step-by-step explanation:

Given that p is at the distance of 3/4 from A to B

it mean that point p divides the line AB into 3:4 ratio.

and

if there are two points (x1,y1) and (x2,y22) which is divided by point p in the ratio m:n then

coordinates of point p (x,y) is given

p (x = (n*x1+m*x2)/m+n , y = (n*y1+m*y2)/m+n )

________________________________________________

Given the points AB

A(2,5)

B(6,9)

m:n = 3:4

thus,

p (x = (4*2+3*6)/7 , y = (4*5+3*9)/7 )

p (x = (4*2+3*6)/7 , y = (4*5+3*9)/7 )

p (x = (26/7 , y = 47/7 )

P ( x = 3.71, y = 6.71)

Thus, coordinates of point p  is (3.71, 6.71) which is  at  3/4 of the distance from A to B for A(2,5) and B(6,9)/

5 0
2 years ago
WILL GIVE BRAINLIEST: What is the local minimum value of the function g(x)=x^4-5x^2+4? (Round answer to the nearest hundredth)
IrinaK [193]

Answer:

Step-by-step explanation:

you can find where the first derivative is 0 to find the critical points

g'(x) = ( x^4 -5x^2 +4)' = 4x³-10x

g'(x) =0, make y =0 to find find where g'(x) is 0

4x³-10x =0 , factor 2x

2x(2x²-5)= 0 , each factor must be 0

2x= 0, so x= 0

2x²-5 =0, so x = ±√5/2

we now have 3 critical points -√5/2, 0, and √5/2

make intervals (-∞, -√5/2), (-√5/2, 0) , (0, √5/2) and (√5/2, +∞)

pick a point to test on each interval: -2, -1, 1 and 2 for example, and

calculate g'(x) = 4x³-10x at those points

for x= -2 we have 4(-2)³-10(-2) = -12 , negative number, decrease

for x= -1 we have 4(-1)³-10(-1) =6, positive number, increase

for x= 1 we have 4(1)³-10(1) = -6, negative number, decrease

for x= 2 we have 4(2)³-10(2) = 12, positive number, increase

we went from a decrease to an increase on intervals (-∞, -√5/2), (-√5/2, 0) so x= - √5/2 ≈ -1.58 is a minimum

we went from a decrease to an increase on intervals (0, √5/2), (√5/2, +∞) so

x= √5/2 ≈ 1.58 is a minimum as well

4 0
2 years ago
BRAINLIEST FOR CORRECT ANSWER!!!
aleksklad [387]

Answer:

B?

Step-by-step explanation:

3 0
2 years ago
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