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AlladinOne [14]
3 years ago
8

suppose there are three consecutive intergers.if two times the first is added to twice the middle, the results is 69 minus the l

argest number. what is the largest number?
Mathematics
1 answer:
belka [17]3 years ago
3 0
3 consecutive means
x, x+1, x+2
OR
x, x-1, x-2

the equation based on givens and first equation is:

2(x) + 2(x+1) = 69 - (x+2)
4x + 2 = 67 - x
5x = 65
x = 13

so the largest would be x+2 or 15
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The value of h(t) when t=\frac{15}{32} is 10.02.

Solution:

Given function h(t)=-16t^2+15t+6.5

To find the value of h(t) when t=\frac{15}{32}:

h(t)=-16t^2+15t+6.5

Substitute t=\frac{15}{32} in the given function.

$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5

            $=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5

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           $=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5

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          $=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5

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        $=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}

        $=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}

        $=\frac{-225+450+416}{64}

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       = 10.02

$h\left(\frac{15}{32} \right)=10.02

Hence the value of h(t) when t=\frac{15}{32} is 10.02.

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