Answer:
B
Step-by-step explanation:
Answer:
The fifth degree Taylor polynomial of g(x) is increasing around x=-1
Step-by-step explanation:
Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:
![P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}](https://tex.z-dn.net/?f=P_5%28x%29%3Dg%28-1%29%2Bg%27%28-1%29%5C%2C%28x%2B1%29%2Bg%22%28-1%29%5C%2C%20%5Cfrac%7B%28x%2B1%29%5E2%7D%7B2%21%7D%20%2Bg%5E%7B%283%29%7D%28-1%29%5C%2C%20%5Cfrac%7B%28x%2B1%29%5E3%7D%7B3%21%7D%20%2B%20g%5E%7B%284%29%7D%28-1%29%5C%2C%20%5Cfrac%7B%28x%2B1%29%5E4%7D%7B4%21%7D%20%2Bg%5E%7B%285%29%7D%28-1%29%5C%2C%20%5Cfrac%7B%28x%2B1%29%5E5%7D%7B5%21%7D)
and when you do its derivative:
1) the constant term renders zero,
2) the following term (term of order 1, the linear term) renders:
since the derivative of (x+1) is one,
3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero
Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is:
as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1
Answer:
His sales that week were $2,160.
Step-by-step explanation:
First, you have to subtract $324 from the amount he earned that week, to find the 5% he got from sales:
$432-$324=$108
Now, you know that he received $108 that represent 5% of his sales and you can use a rule of three to find the amount that represents 100% which would be his sales that week:
5% → 108
100% → x
x=(100*108)/5=2160
According to this, the answer is that his sales that week were $2,160.
Answer:
x=7
Step-by-step explanation:
potato^3