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3 years ago

Find x if AB = 9, BC = 2x - 5, and AC = x + 9

Mathematics

2 answers:

Oxana [17]3 years ago

5 0

Answer:

x = 5

Step-by-step explanation:

Using the fact that line segments AB and BC are parts of the whole line segment AC, we can write the following equation:

AB + BC = AC

Now, using the given values, we can substitute in for the equation and solve for x:

AB + BC = AC

9 + 2x - 5 = x + 9

2x + 4 = x + 9

x = 5

Thus, we have found that for these sets of equations for these line segments, our value for x should be 5.

Cheers.

drek231 [11]3 years ago

5 0

Answer:

x=5

Step-by-step explanation:

AB + BC = AC

9+ 2x-5 = x+9

Combine like terms

2x+4 = x+9

Subtract x from each side

2x+4-x = x+9-x

x+4 = 9

Subtract 4 from each side

x+4-4 = 9-4

x=5

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Two of the three sides of a triangle are 20 and 15. Which of the following numbers is not a possible perimeter of the triangle?

fgiga [73]

e. 72.

Let x be the measurement of the 3rd side.

x should be greater that the difference of 2 sides
x should be less than the sum of 2 sides

20 - 15 < x < 20 + 15
5 < x < 35

We can assume that x = 35 the maximum measurement of the 3rd side.

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3 years ago

What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?

Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

$6x+y=-5$

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:

Equation of Line that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?

Solution:

$x-6y=42$ ..................Given

which can be written as

$y=mx+c$

Where m is the slope of the line

∴ $y=\dfrac{x}{6}-7$

On Comparing we get

$Slope = m = \dfrac{1}{6}$

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

$m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6$

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,

i.e equation in point - slope form

$(y-y_{1})=m(x-x_{1})$

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

$(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line$

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

$6x+y=-5$

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3 years ago

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Svetllana [295]

Answer:

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The diagonals of a parallelogram bisect with each other at the point of intersection with equal sides across the point of intersection.

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