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levacccp [35]
3 years ago
15

Is 1/4 bigger than 3/4

Mathematics
2 answers:
Leto [7]3 years ago
7 0
<span> The larger the numerator, the larger the fraction.
3/4 is bigger then 1/4.
You could also draw a model :D
Your answer is <em>no.</em>
</span>
Reika [66]3 years ago
7 0
No. three fourths is bigger
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Anyone Know This Answer ASAP ?
Luda [366]

multiply 35 by tan(42)

 this equals 31.5141

rounded to 31.51

4 0
3 years ago
The graph shows the attendance at a hockey game, and the rate at which the fans enter and exit the
Strike441 [17]

Answer:

The answer is below

Step-by-step explanation:

From the graph, we can see that both segment 1 and segment 2 are positive slopes (as the time increases, the number of people increases)

Segment 1 is more steep than segment 2 (the number of people increases in segment 1 more than segment 2). This means that the number of people entering the arena in segment 1 was higher than the rate of people entering the arena in segment 2.

8 0
3 years ago
The area of triangle ABC is _____.
Marizza181 [45]
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 
SEE ATTACHED IMAGE.
 
Using Heron's Formula we can find the area of the triangle.
 A = root (s (s-a) * (s-b) * (s-c))
 s = (a + b + c) / 2
 Where,
 s: semi-perimeter
 a, b, c: sides of the triangle
 Substituting values:
 s = (15 + 16 + 20) / 2
 s = 25.5
 s = 26
 The area will be:
 A = root (26 * (26-15) * (26-16) * (26-20))
 A = 130.9961832
 A = 130 u ^ 2
 Answer:
 
The area of triangle ABC is:
 
C.
 
130 u ^ 2

5 0
3 years ago
A certain university recently calculated the number of days that its students took to complete their master's degrees. It took 1
mixer [17]

Answer:

c) 700

Step-by-step explanation:

Add 800 and 600, and then divide by the number of number, or in this case, two. This should give you 700.

8 0
2 years ago
Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo
Ilya [14]

Answer:

x^6+3x^3+3+\dfrac{1}{x^3}

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}

4 0
3 years ago
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