You didn't give the multiple choice so no one can help you do make sure to include that next time
Answer:
A) 20.82 > 20.55
Step-by-step explanation:
Hopefully, your issue is with the symbols (< vs >) rather than actually determining which number is larger or smaller.
The wide-open end of the symbol (the left side, in the case of >) indicates the larger (more positive) number.
So, the meanings of the symbols are ...
> — "is greater than"
< — "is less than"
The only true statement of those listed is ...
20.82 is greater than 20.55, or 20.82 > 20.55 . . . . selection A
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When writing number comparisons, I like to use the < symbol, because it puts the numbers in number-line order. That is, the smaller (or more negative) number is on the left, just as it is on a number line.
You trade the places of the numbers when changing the symbol. For example, answer choice A could be rewritten as ...
20.55 < 20.82
You know that 20.55 is to the left of 20.82 on the number line, so you know this statement is true.
The result is 1/3.
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The first attempt in the attached picture has parentheses in the wrong place for the second term. This simplifies to
.. (-5/-3)*(-4) +(10 -3)
.. = -20/3 +7
.. = -(6 2/3) +7
.. = 1/3
The simple interest formula is A = P(1 + rt) in which A is the total of money after interest, P is your principal (starting) amount, r is the interest rate, and t is the amount of time.
For 1), plug in your variables to get A = 1500(1 + (7/100*1.5)). Simplify, and you'll get A = 1500*1.105, and finally your answer, $1,657.50.
<span>For 2), add your interest and principal amount, then plug in your variables to get 676 = 520(1 + 5r). Distribute to get 676 = 520 + 2600r. Subtract 520 from 676 to get 156 = 2600r, then divide both sides by 2600 to get a rate of 0.06, or 6%.
For 3), add your interest and principal amount, then plug in your variables to get 1599 = 1300(1 + 5.75t). Distribute to get 1599 = 1300 + 7475t. Subtract 1300 from both sides to get 299 = 7475t, and then divide both sides by 7475 to get .04 = t, or a time period of four years.
The other two problems can be solved using the formula and steps described above. If you still need help with them, leave a comment and I will solve those as well. </span>
