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Anvisha [2.4K]
3 years ago
6

Find 32% of 35.? plzz help me with this

Mathematics
2 answers:
Anna35 [415]3 years ago
7 0
32% of 35 is 32% times 35, which is 11.2
Rainbow [258]3 years ago
4 0
<span>32% of 35

First, change the percentage into a decimal. This is done by moving the decimal point two points to the left.
32% = 0.32

0.32 of 35

Whenever you see the word "of", immediately think of multiplication. Replace "of" with "</span>×".
0.32 × 35 = 11.2

So the answer is 11.2.
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Please help me thanks
PilotLPTM [1.2K]
6x + 45 + 3x = 180
9x - 45 = 180
9x = 135
x = 15
8 0
2 years ago
I WILL MARK BRAINLIEST!!!! An underground mine elevator descends 12% of the total depth every minute. The total depth of the ele
Dahasolnce [82]

Answer:

after 1 Min it's -9

after 2 mins it's -1.08

Step-by-step explanation:

12% X 75 = 9

12% X 9 = 1.08

3 0
3 years ago
Read 2 more answers
What is 1 2/3 multiplied by 4 1/2
horrorfan [7]
Change the mixed numbers into improper fractions:
5/3 X 9/2

Reduce - the 3 and 9 can be simplified
5/1 X 3/2

multiple numerators and denominators
15/2

Not sure how you need the answer - i would change it into a mixed number
7 1/2
3 0
3 years ago
The radius of a circle is 8 feet. What is the area of sector bounded by a 90° arc?
Lera25 [3.4K]

Since 90 degree is 1/4 of a circle, the area will be 1/4 th area of the full circle.

The radius is given by, r = 8 ft, therefore, the area of the full circle is,

\begin{gathered} A=\pi\times r^2 \\ A=3.14\times8^2=200.96ft^2 \end{gathered}

Therefore, the area of the sector is,

A^{\prime}=\frac{1}{4}\times200.96ft^2=50.24ft^2\begin{gathered} A^{\prime}=\frac{\theta}{360}\times\pi\times r^2 \\ \text{ =}\frac{\text{90}}{360}\times\pi\times8^2 \\ \text{ =}\frac{1}{4}\pi\times64=16\pi \end{gathered}

4 0
1 year ago
What is the similarity ratio of the smaller to the larger similar cylinders?
lbvjy [14]
\bf \qquad \qquad \textit{ratio relations}&#10;\\\\&#10;\begin{array}{ccccllll}&#10;&Sides&Area&Volume\\&#10;&-----&-----&-----\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}&#10;\end{array} \\\\&#10;-----------------------------\\\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\&#10;-------------------------------\\\\

\bf \cfrac{smaller}{larger}\qquad \cfrac{s}{s}=\cfrac{\sqrt{48\pi }}{\sqrt{75\pi }}\implies \cfrac{s}{s}=\cfrac{\sqrt{(2^2)^2\cdot 3}}{\sqrt{5^2\cdot 3}}\implies \cfrac{s}{s}=\cfrac{4\sqrt{3}}{5\sqrt{3}}&#10;\\\\\\&#10;\cfrac{s}{s}=\cfrac{4}{5}
8 0
3 years ago
Read 2 more answers
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