All categories

3 years ago

Write the absolute value equation given the transformations

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

7 0

Answer:

y = - 0.5 | x - 5 | + 2 

Step-by-step explanation:

g(x) = |x|

$1^{st}$ step - shifts right 5 units: g(x + 5) = | x - 5 |

$2^{nd}$ step - shifts up 2 units: g(x + 5) + 2 = | x - 5 | + 2

$3^{rd}$ step - reflected: - g(x + 5) + 2 = - | x - 5 | + 2

$4^{th}$ step - stretched by 0.5: y = - 0.5 | x - 5 | + 2

y = - 0.5 | x - 5 | + 2

You might be interested in

Graphing rational functions. I need help asap!!!!

Anastaziya [24]

Answer:

Vert. asymptote: x = {-3, 2}

Horiz. asymptote: y = 0

x-int: None

Question 3.

a. There is no hole

b. Vert. asymptote: x = {-2, 2}

c. f(x) = 0: x = {0, -1/2}

d. The graph has no hole at (-2, 4)

Question 4.

a. Vert. asymptote: x = {-2, 2}

b. f(x) = 0: x = {0, -1/2}

c. Horizontal asymptote: y = 2

d. The graph has no hole

I'm a bit confused. Some of the things stated in the question aren't true like how there are holes in places where there aren't.

6 0

3 years ago

I NEED HELP WITH THIS MATH PROBLEM!!!!

Natalka [10]

Answer:

Step-by-step explanation:

6f - 1 + 7f - 8 = 6f + 7f - 1 - 8

= 13f - 9

Combine like terms. Like terms have same variable with same power.

6 0

3 years ago

Read 2 more answers

Solve the equation for the variable. 15.25 – 3.8x = -26.75 +2.2x x = [?]

nirvana33 [79]

X=-2.3

I hope this is helpful! Let me know if you need anymore help!

4 0

2 years ago

Someone please give me the answers...And thank you

ale4655 [162]

Answer:

Step-by-step explanation:

1) 4x + 3 <= 3x - 5

Subtract 3 from both sides

4x + 3-3 <= 3x - 5 -3

4x <= 3x - 8

Subtract 3x form both sides

4x - 3x <= 3x -3x - 8

x <= -8

6 0

3 years ago

Read 2 more answers

Use Newton's Method to approximate the zero(s) of the function. Continue the iterations until two successive approximations diff

liubo4ka [24]

Answer:

There is only one real zero and it is located at x = 1.359

Step-by-step explanation:

After the 4th iteration the solution was repeating the first 3 decimal places. The formula for Newton's Method is

$x_{n}-\frac{f(x_{n}) }{f'(x_{n}) }$

If our function is

$f(x)=x^5+x-6$

then the first derivative is

$f'(x)=5x^4+1$

I graphed this on my calculator to see where the zero(s) looked like they might be, and saw there was only one real one, somewhere between 1 and 2. I started with my first guess being x = 1.

When I plugged in a 1 for x, I got a zero of 5/3.

Plugging in 5/3 and completing the process again gave me 997/687

Plugging in 997/687 and completing the process again gave me 1.36976

Plugging in 1.36976 and completing the process again gave me 1.359454

Plugging in 1.359454 and completing the process again gave me 1.359304

Since we are looking for accuracy to 3 decimal places, there was no need to go further.

Checking the zeros on the calculator graphing program gave me a zero of 1.3593041 which is exactly the same as my 5th iteration!

Newton's Method is absolutely amazing!!!

5 0

3 years ago