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3 years ago

Simplify the expression. 1.7 – 2.7 – 1.34 + 4.9 – 1.48

Mathematics

2 answers:

lukranit [14]3 years ago

6 0

Work from left to right
= -1 - 1.34 + 4.9 - 1.48
=-2.34 + 4.9 - 1.48
= 2.56 - 1.48
= 1.08 answer

Lelechka [254]3 years ago

4 0

= -1 - 1.34 + 4.9 - 1.48

=-2.34 + 4.9 - 1.48

= 2.56 - 1.48

= 1.08 answer

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What is the total price charged for goods that cost $9.50 and have a 6% sales tax?

Anika [276]

9.50×.06= .57+9.50=10.07 the total price is $10.07 with tax

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4 years ago

Read 2 more answers

A ball is launched upward at 14 m/s from a platform 30 m high.Find the maximum height the ball will reach and how long it will t

BartSMP [9]

Answer:

The ball will reach a maximum height of 39.993 meters after 1.428 seconds.

Step-by-step explanation:

Let suppose that no non-conservative forces acts on the ball during its motion, then we can determine the maximum height reached by the Principle of Energy Conservation, which states that:

$K_{1}+U_{g,1} = K_{2}+U_{g,2}$ (1)

Where:

$K_{1}$ , $K_{2}$ - Initial and final translational kinetic energies, measured in joules.

$U_{g,1}$ , $U_{g,2}$ - Initial and final gravitational potential energies, measured in joules.

By definition of translational kinetic energy and gravitational potential energy we expand and simplify the expression above:

$\frac{1}{2}\cdot m\cdot v_{2}^{2}+m\cdot g\cdot y_{2}= \frac{1}{2}\cdot m\cdot v_{1}^{2}+m\cdot g\cdot y_{1}$ (2)

Where:

$m$ - Mass of the ball, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

$v_{1}$ , $v_{2}$ - Initial and final speed of the ball, measured in meters per second.

$y_{1}$ , $y_{2}$ - Initial and final heights of the ball, measured in meters.

The final height of the ball is determined by the following formula:

$v_{2}^{2}+2\cdot g\cdot y_{2} = v_{1}^{2}+2\cdot g\cdot y_{1}$

$v_{1}^{2}-v_{2}^{2}+2\cdot g \cdot y_{1}=2\cdot g\cdot y_{2}$

$y_{2} = y_{1}+\frac{v_{1}^{2}-v_{2}^{2}}{2\cdot g}$ (3)

If we know that $y_{1} = 30\,m$ , $v_{1} = 14\,\frac{m}{s}$ , $v_{2} = 0\,\frac{m}{s}$ and $g = 9.807\,\frac{m}{s^{2}}$ , the maximum height that the ball will reach is:

$y_{2} = 30\,m + \frac{\left(14\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$y_{2} = 39.993\,m$

The ball will reach a maximum height of 39.993 meters.

Given the absence of non-conservative forces, the ball exhibits a free fall. The time needed for the ball to reach its maximum height is computed from the following kinematic formula:

$t = \frac{v_{2}-v_{1}}{-g}$ (4)

If we know that $v_{1} = 14\,\frac{m}{s}$ , $v_{2} = 0\,\frac{m}{s}$ and $g = 9.807\,\frac{m}{s^{2}}$ , then:

$t = \frac{0\,\frac{m}{s}-14\,\frac{m}{s} }{-9.807\,\frac{m}{s^{2}} }$

$t = 1.428\,s$

The ball will take 1.428 seconds to reach its maximum height.

6 0

3 years ago

35 POINTS

miv72 [106K]

Answer:

Step-by-step explanation:

520/8=65 so approximately 65 kids play soccer

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3 years ago

The perimeter of a rectangle is 40 inches. If the length is four less than twice the width, find the dimensions and area

Vinvika [58]

Answer:

L = 12 inches and W = 8 inches

Area = 96 in^2

Step-by-step explanation:

Perimeter(P) = 2(width) + 2(length)

Let W = width and L = length

P = 2W + 2L

L = 2W - 4

Substitute: P = 2W + 2(2W - 4)

P = 6W - 8

P = 40 inches

40 = 6W - 8

6W = 48

W = 8

L = 2W - 4

L = 2(8) - 4

L = 12

L = 12 inches and W = 8 inches

===============================

Check to see if this works:

P = 2W + 2L

P = 2(12) + 2(8)

P = 24 + 16

P = 40 inches YES

========

Area = WxL

Area = (12)*(8)

Area = 96 in^2

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2 years ago

1.00

jenyasd209 [6]

Answer:

Step-by-step explanation:

Plug in 3 into both expressions

Then add those results

2(3)+21=6+21=27

3-24 =-21

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6 is the sum of 27 and -21

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4 years ago