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navik [9.2K]
4 years ago
7

X+2 x²+1 What’s the answer

Mathematics
1 answer:
Ivan4 years ago
8 0

Answer:

3x^2+1

Step-by-step explanation:

combine terms

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Should it be m>m+m>n+mo for first step
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Simplify the expression. Please help me ​
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Step-by-step explanation:

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7 0
3 years ago
At a sale on winter clothing Cody brought two pairs of gloves and four hats for $43.00 tori bought two pairs of gloves and two h
Julli [10]

Answer:

Cost of one glove pair is $ 8.50 and the cost of one hat is $6.50

Step-by-step explanation:

Let g represents the cost of one gloves pair

h represents the cost of one hat

Then

Cody brought two pairs of gloves and four hats for $43.00

This can be written as

2g + 4h = 43-------------------(1)

Tori bought two pairs of gloves and two hats for 30.00

This can be written as

2g + 2h = 30------------------(2)

Subtracting (2) from (1)

2g + 4h = 43

2g + 2h = 30

(-)

--------------------------

0g + 2h = 13

------------------------------------

2h =13

h = 13 / 2

h = 6.5---------------------(3)

Substituting (3) in (2)

2g + 2(6.5) = 30

2g + 13 = 30

2g = 17

g = 17 / 2

g = 8.5

So one hat is $6.50 and one pair of gloves is $8.50.  

6 0
4 years ago
Find the definite integral from 0 to 1/16 of arcsin(8x)/sqrt(1-64x^2)dx
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\displaystyle\int_0^{1/16}\frac{\arcsin8x}{\sqrt{1-64x^2}}\,\mathrm dx

First let y=8x, so that \mathrm dx=\dfrac{\mathrm dy}8 to write the integral as

\displaystyle\frac18\int_0^{1/2}\frac{\arcsin y}{\sqrt{1-y^2}}\,\mathrm dy

Now recall that (\arcsin y)'=\dfrac1{\sqrt{1-y^2}}, so substituting z=\arcsin y should do the trick. The integral then becomes

\displaystyle\frac18\int_0^{\pi/6}z\,\mathrm dz=\frac1{16}z^2\bigg|_{z=0}^{z=\pi/6}=\frac{\pi^2}{576}
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3 years ago
Factor. (GCF)
saw5 [17]
Answer: 6(4a + 2b - 5)
8 0
3 years ago
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