Answer:
If the second of the three numbers is
n
, then the first and third are
n- 1
and n
+
1
, so we find:
117
=
(
n
−
1
)
+
n
+
(
n
+
1
)
=
3n
Dividing both ends by
3 we find:
n
=
117/ 3
=
39
So the three numbers are:
38
,
39
,
40
Step-by-step explanation : I hope it helps please don't forget to mark me brainliest . :)
1) 5
2) zero
3) <span>Step 1: 12x + 15 = 12
Step 2: 12x = −3
4) 10
5) 2
This took me a long time to do so I hope this was beneficial :)) !! (btw I am absolutely sure about every answer. I checked my work plenty of times :)</span>
We first use midpoint formula
X1+X2 divided by 2 we want x for midpoint.
Y1+Y2 divided by 2 we want Y for midpoint
10-4 divided by 2 =3
7-0 divided by 2 =7/2
therefore midpoint= (3;7/2)
Answer:
First step to solving the equation is to subtract 10 on both sides:
10 - 10 + 5x =65 -10
5x = 55
Then, we divide by 5 on both sides!
5x ÷ 5 = 55 ÷ 5
x = 11
Our result is 11, so the answer to the problem is 11
I hope I was helpful!
Given that the height of the disc is modeled by the function:
h=-16t^2+20t+6
a] The maximum height will be as follows:
At maximum height:
h'(t)=0
from h(t)
h'(t)=-32t+20=0
thus
t=20/32
t=5/8 sec
thus the maximum height will be:
h(5/8)=-16(5/8)^2+20(5/8)+6
=12.25 ft
b] <span>How long will it take the disc to reach the maximum height?
</span>time taken to reach maximum height will be:
from h(t)
h'(t)=-32t+20=0
thus
t=20/32
t=5/8 sec
thus time taken to reach maximum height is t=5/8 sec
c]<span>How long does it take for the disc to be caught 3 feet off the ground?
</span>h(t)=-16t^2+20t+6
but
h(t)=3
thus
3=-16t^2+20t+6
solving for t we get:
0=-16t^2+20t+3
factoring the above we get:
t=5/8-/+√37/8
t=-1.5256 or 2.776
since there is no negative time we pick t=2.776
Hence time taken for the disc to be caught 3 ft from the ground is 2.776 ft
