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devlian [24]
3 years ago
7

What ordered pair is missing from the input-output table?

Mathematics
2 answers:
AlexFokin [52]3 years ago
7 0

Answer:

(5,15)

Step-by-step explanation: to me it is just obvious

konstantin123 [22]3 years ago
5 0

Answer:

(5, 15)

Step-by-step explanation:

(X, Y) so if the x is 5 then 5 replaces x and if the y is 15 the 15 replaces y. So it would be (5,15)

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Step-by-step explanation:

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Robert has 26 coins that are all nickels and dimes. The value of the coins is $1.85. How many of each does he have?
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Step-by-step explanation:

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5 0
2 years ago
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8 0
3 years ago
Read 2 more answers
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}&#10;\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}&#10;\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}&#10;\\&#10;\\ \text{z-score} = \frac{720 - 600}{100}&#10;\\&#10;\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) &#10;\\ = P(z \ \textgreater \  1.2)&#10;\\ = 1 - P(z \leq 1.2)&#10;\\ = 1 - 0.885&#10;\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
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