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devlian [24]
3 years ago
7

What ordered pair is missing from the input-output table?

Mathematics
2 answers:
AlexFokin [52]3 years ago
7 0

Answer:

(5,15)

Step-by-step explanation: to me it is just obvious

konstantin123 [22]3 years ago
5 0

Answer:

(5, 15)

Step-by-step explanation:

(X, Y) so if the x is 5 then 5 replaces x and if the y is 15 the 15 replaces y. So it would be (5,15)

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What is the answer to 3 = x/12 + 3?
Citrus2011 [14]
The answer is 3.25 hundredths your welcome and thank you for letting me answer your answer bye.
4 0
3 years ago
Determine the numerical length of JK.​
Zarrin [17]

Answer:

30

So the two sectors add to the full length:

JK + IJ = IK

x+6 + 9 = 2x

Rearrange:

x=15

So the numerical length:

2x

2*15

30

5 0
3 years ago
Read 2 more answers
Check my proof? Two diagonals of a parallelogram bisect each other?
SIZIF [17.4K]
Your proof is correct and very well done
6 0
3 years ago
Becky bought a bag of mixed chocolates that have either a toffee or nut center. Her and four friends pulled out the first eleven
denpristay [2]

Answer

Part A

Probability that the next chocolate will have a toffee center = (8/11)

Part B

Expected number of chocolates with nut centers = 18 nut centers

Part C

Probability of the picking three consecutive chocolates with nut centers

= (27/1331)

= 0.0203

Explanation

The first 11 chocolates had 8 toffee and 3 nut centers.

The result from these first 11 picks will be used to calculate the rest of the probability or make predictions.

So, for the first part of the question.

Probability that the next chocolate will have a toffee center

= (8/11)

Part B

If there are 66 chocolates left in the bag, how many do you expect to have a nut center?

Probability of picking a chocolate with nut center = p = (3/11)

Number of chocolates in total = n = 66

Expected number of chocolates with nut centers

= np

= (66) (3/11)

= 18 nut centers

Part C

What is the probability that the next 3 pulled do have a nut in the center?​

Probability of picking a chocolate with nut center = (3/11)

Probability of the picking three consecutive chocolates with nut centers

= (3/11) × (3/11) × (3/11)

= (27/1331)

= 0.0203

Hope this Helps!!!

3 0
1 year ago
Mathematics <br> Simple events likelihood experimental probability
saw5 [17]

Problem 1

Answer: Closer to 1

Explanation:

There are 20 gumballs total. Half of this is 20/2 = 10 gumballs. If there's more than 10 of one color, then the probability of getting that color is closer to 1, than it is to 0. Here we have 12 pink which is greater than 10, so that's why the answer is closer to 1.

================================================

Problem 2

Answer: Closer to 0

Explanation:

The amount of green (3) is less than 10, so that's why the probability is closer to 0 than it is to 1. We can see that 3/20 = 0.15 is less than 0.50

================================================

Problem 3

Answer: Closer to 0

Explanation:

We have a similar situation compared to problem 2. This time we have 5/20 = 0.25 which is less than 0.50

================================================

Problem 4

Answer: 48% chance; fairly likely

Explanation:

We have 12 green out of 25 total, so the probability of choosing green is 12/25 = 0.48 = 48%. While this probability is not over 50%, I still say it's fairly likely considering the other colors lead to smaller probabilities. For instance, purple has a chance of 6/25 = 0.24 = 24% and orange has a probability of 2/25 = 0.04 = 4%, both of which are smaller than 48%

3 0
3 years ago
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