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3 years ago

Please help me please will give brainliest to anyone who is good show your work

Mathematics

1 answer:

lara [203]3 years ago

7 0

Answer:

B - 1/9

Step-by-step explanation:

I don't really know how to explain how I got it because I'm only in middle school in pre-algebra, but I did teach this to myself online haha, so here we go. Daneille rolled the dice 90 times, it only landed on 6 10 times. That is 10/90 which, simplified, is 1/9.

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Cary and his brother took a road trip together. The total number of miles they drove was more than 200. Cary drove for 50 miles.

Brilliant_brown [7]

Answer:

Step-by-step explanation:

The trick is not to include anything under and including 150 miles. So A B and C are not to be checked.

D and E are both true.

5 0

3 years ago

Read 2 more answers

What is the probability that a card drawn randomly from a standard deck of 52 cards is a red eight Express your answer as a frac

vekshin1

Answer:

=1/26

Step-by-step explanation:

In a 52 card deck there are 2 red 8's ( hearts and diamonds)

P(red 8) = number of red 8's / total

=2/52

=1/26

4 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$