DEF is a isosceles right triangle, so DE =EF. apply Pythagoras:
DF² = DE² + EF² , BUT DE = DF .then DB² = 2DE² = 28²
DE² = 28/2 = 14 and DE = √14 = 3.71 ≈3.7
16 m
Step-by-step explanation:
The answer would be D. It says the length is 10 millimeters less than TWICE the width, so it would be 10 millimeters greater than the original width.
Answer:
The formula has a typo. Should be
V= (1/2) ((4pir^3)/(3))+ pi r^2 (y-r)
or
v = 2π/3 r^3 + πr^2 (y-r)
= πr^2 y - π/3 r^3
2πryr' + πr^2 - πr^2 r' = 0
r' = r/(r-2y)
r'(6) = 2/(2-12) = -1/5
dr = dr/dy * dy
= -1/5 (-.25) = 0.05
so, r = 2.05
Step-by-step explanation:
280 because its in the middle