Answer:
1Burning of fossil fuel
2Deforestation
3Waste disposal in landfills
Explanation: took test:)
Answer:
Hello some part of your question is missing below is the missing part
2. What is the force on the charged particle if it is now located at the 0V potential difference line? (mN) (hint: The electric field can be obtained as above using the 0V and -10V equipotential lines.)
answer :
1) 0.8 mN
2) 0.8 mN
Explanation:
Given data:
1) Calculate the force on the charged particle
q = 80 μC , Va = 30v , Vb = 40v, ∝ = 1 m
E = ( Δv ) / ∝
= ( Vb - Va ) / ∝
F = qE
= 80 μC * ( 40 - 30 ) / 1 m
= 800 μC
F = 0.8 mN
<u>2) Calculate the force on the charged particle when it is located at 0V</u>
Va = -10V , Vb = 0V, q = 80 μC, ∝ = 1 m
F = qE
where E = ( 0 - ( -10 ) / 1
F = 80 μC * ( 0 - ( -10 ) / 1
= 800 μC = 0.8 mN
Answer:
61 degrees, I just did the test.
Explanation:
Answer:
s = 147.54 m
Explanation:
given,
initial velocity,u = 45 mi/h
1 mph = 0.44704 m/s
45 mph = 45 x 0.44704 = 20.12 m/s
final velocity, v = 65 mi/h
v = 65 x 0.44704 = 29.06 m/s
time, t = 6 s
acceleration,
a = 1.49 m/s²
distance travel by the car
using equation of motion
v² = u² + 2 a s
29.06² = 20.12² + 2 x 1.49 x s
2.98 s = 439.6692
s = 147.54 m
distance traveled by the car is equal to 147.54 m