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3 years ago

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How does a photocopier use static electricity? a. Positively charged ink is attracted to negatively charged paper c. Negatively

charged toner is attracted to a positively charged image b. Positively charged ions power the machine d. Negatively charged ink is repelled from the original onto the copy plate

1 answer:

Pavlova-9 [17]3 years ago

5 0

The answer is b. sjhfgae

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30 PTS NEED THIS FAST

bogdanovich [222]

The middle one would heat up the fastest as glass traps heat, black absorbs heat well and silver is a good conductor of heat however you would want to re-phrase that

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3 years ago

Read 2 more answers

Slick Willy is in traffic court (again) contesting a $50.00 ticket for running a red light. “You see, your Honor, as I was appro

natta225 [31]

Answer and Explanation:

$Greetings!$

$I'm~Isabelle~Williams~and~I~will~be~answering~your~question!$

$Given:$

$Wave~length~ of~ red ~ light = 683~ nm$

$Wave ~length ~of~ yellow~ light = 576~ nm$

$The~ speed ~of~ the~ Slick~ Willy~ can~ be:$

$\boxed{~f'=(\frac{v+v_{o} }{v} )f~}$

$Where:$

$f'=observed~frequency$

$f=actual~frequency$

$v=speed~of~light$

$v_{o}=~speed~of~observer$

$Plug~in~the~values:$

$683\times 10^-^9=576\times 10^-^9 ~(1+\frac{v_{o} }{3\times 10^8} )$

$\frac{683}{576}=1+\frac{v_{o} }{3\times 10^8}$

$\frac{v_{o} }{3\times 10^8} =\frac{683}{576}=-1$

$v_{o}=0.186\times 3\times 10^8$

$v_{o}=0.558\times 10^8 ~m/s$

$Hope~this~helps!~Have~an~amazing~day~ahead!~$

$-Isabelle~Williams$

6 0

4 years ago

If every object that has mass has gravity why do I only notice the gravity of Earth

Nesterboy [21]

There are times where the mass is less than the force of gravity or the gravitational pull. The gravitational pull will overpower the mass of the object, which is why you only notice the force of gravity and not the mass

4 0

4 years ago

The moon has a mass of 1×10^22 kg, and the gravitational field strength at a distance r from the planet is 0.001 n/kg. what is t

CaHeK987 [17]

When I divided by 6, I got W(moon) = mg(moon) = 10 x 10/6 = 16.7N (the moon's gravity is only 1/6 that of Earth in this case). 100N is equal to W(Earth) = mg(Earth) = 10 x 10. On the moon and the Earth, m = 10 kg.

How can you determine the strength of Earth's gravitational field at the moon?

M = 6 10 24 K g is the mass of the earth, and g = - G M R 2 is the gravitational field of the earth at the point of the moon. The distance between the earth and moon is 84 10 8 meters. field of gravitation.

How do you determine the distance between Earth and the moon where the gravitational field is at its weakest?

You only discover points where the forces from all of the different local bodies are in balance, or equal to each other, because there is no place in the universe where the gravitational field intensity is zero. All bodies, not just the Earth and Moon, must be taken into account in the computation to arrive at these positions.

To know more about gravitational field strength at moon visit;

brainly.com/question/20909424

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4 0

2 years ago

While riding TRAX at a constant speed of 16 m/s you walk toward the front of the car at 5 m/s.

AVprozaik [17]

Speed of the TRAX is given as 16 m/s so let say it is given as

$v_t = 16 m/s$

now our speed towards the front end is given by 5 m/s so this is the relative speed of us with respect to TRAX

let say this speed is given as

$v_1t = 5 m/s$

now we need to find the speed with respect to someone standing outside the TRAX

so here we need to find the net speed in ground frame and hence we can use the formula of relative speed

$v_{1t} = v_1 - v_t$

$v_1 = v_{1t} + v_t$

$v_1 = 5 + 16$

$v_1 = 21 m/s$

so someone outside the TRAX will see our speed as 21 m/s

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3 years ago