Answer:
v = 29.4 m / s
Explanation:
For this exercise we can use the conservation of mechanical energy
Lowest starting point.
Em₀ = K = ½ m v²
final point. Higher
= U = m g h
Let's use trigonometry to lock her up
cos 60 = y / L
y = L cos 60
Height is the initial length minus the length at the maximum angle
h = L - L cos 60
h = L (1- cos 60)
energy is conserved
Em₀ = Em_{f}
½ m v² = mgL (1 - cos 60)
v = 2g L (1- cos 60)
let's calculate
v² = 2 9.8 3.0 (1- cos 60)
v = 29.4 m / s
Answer:
<u><em>Rate of dissolving compounds:</em></u>
If we increase the temperature of the solution, then the dissolving compound would dissolve more easily.
<u><em>Boiling Point of Compounds:</em></u>
If the inter-molecular forces of any compound is really strong, then the boiling point of the compound would be really high.
The correct answer is 1.25 because it is 1/2 of 1 1/2 and that is 1.25.
Answer:
Explanation:
Rate of dissipation of energy at resistor
= I² R = 296
current I² = 296/R = 296 / 300
I = 0.9933 A.
Impedence Z = V / I = 500 / .9933
= 503 ohm.
B ) Let it be V
voltage across resistance = 300 x .9933 = 298 v
Now 500² = 298² + V²
V = 401 v
C) Power factor = R / Z
=300 / 503
= 0.596
