Need help please see attached
1 answer:
You might be interested in
There are two acceptable ways of solving this. I'll show both (just in case one of them doesn't align with the information from your textbook).
Option 1 (fast and easy):
The following is the equation for the area of a regular pentagon with side length s.
Plug s=12 into the equation.
The third choice should be your answer.
Option 2 (much more complicated):
The area of a regular polygon can be solved with the following formula.
Let's solve for the apothem.
A pentagon can be divided into 5 congruent isosceles triangles. The vertex angle will be 360/5, or 72 degrees.
An isosceles triangle can be divided into two right triangles. One of the angles of the right triangle will be 72/2, or 36 degrees.
The leg opposite of the 36 degree angle will be 12/2, or 6 inches long.
The apothem is about 8.26 inches.
The perimeter is 12*5, or 60 inches.
(it seems that we're off by 0.1 due to rounding errors)
The answer is the third choice. Hope this helps! :)
Option 1 (fast and easy):
The following is the equation for the area of a regular pentagon with side length s.
Plug s=12 into the equation.
The third choice should be your answer.
Option 2 (much more complicated):
The area of a regular polygon can be solved with the following formula.
Let's solve for the apothem.
A pentagon can be divided into 5 congruent isosceles triangles. The vertex angle will be 360/5, or 72 degrees.
An isosceles triangle can be divided into two right triangles. One of the angles of the right triangle will be 72/2, or 36 degrees.
The leg opposite of the 36 degree angle will be 12/2, or 6 inches long.
The apothem is about 8.26 inches.
The perimeter is 12*5, or 60 inches.
(it seems that we're off by 0.1 due to rounding errors)
The answer is the third choice. Hope this helps! :)