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3 years ago

What's the estimate for 2-9

Mathematics

1 answer:

andrew11 [14]3 years ago

5 0

The estimate between 2 and 9 is 7

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If a line has a slope of -4 and a u intercept of 1, which of the following is it's graph?

3241004551 [841]

Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing

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3 years ago

8.25 × 10–4 in standard form.

Elanso [62]

The 10^-4 means that the decimal point is 4 places to the left of where it is in 8.25 (if the exponent was positive the decimal point would be to the right). If you move the decimal point 4 places to the left you get an answer of 0.000825 which is 8.25 * 10^-4 in standard form.

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3 years ago

12. Ms. Lacy wants to work out. Drop It Like It's Hot gym charges a monthly rate of $25 and

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Answer:

more than 12 classes

Step-by-step explanation:

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3 years ago

What are the solutions to the equation y2 – 1 = 48?

Furkat [3]

${y}^{2} - 1 = 48 \\ {y}^{2} = 49 \\ y = \sqrt{49} \\ y = - 7 \: or \: 7$

${y}^{2} - 1 = 24 \\ {y}^{2} = 25 \\ y = \sqrt{25} \\ y = - 5 \: or \: 5$

Hope this helps. - M

6 0

3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago