First, square both sides. This will cancel out the radical.

(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6
Answer: The distance between the girls is 362.8 meters.
Step-by-step explanation:
So we have two triangle rectangles that have a cathetus in common, with a length of 160 meters.
The adjacent angle to this cathetus is 40° for Anna, then the opposite cathetus (the distance between Anna and the tower) can be obtained with the relationship:
Tan(A) = opposite cath/adjacent cath.
Tan(40°) = X/160m
Tan(40°)*160m = 134.3 m
Now, we can do the same thing for Veronica, but in this case the angle adjacent to the tower is 55°
So we have:
Tan(55°) = X/160m
Tan(55°)*160m = X = 228.5 m
And we know that the girls are in opposite sides of the tower, so the distance between the girls is equal to the sum of the distance between each girl and the tower, then the distance between the girls is:
Dist = 228.5m + 134.3m = 362.8m
Y^-5
x^-5
because you have to put together all the x and then put all the y's together
5 5/9
5 * 5/9
25/9
The correct answer is 25/9, as shown above.
A = a^2
112 = a^2
sqrt 112 = a
sqrt 16 * sqrt 7 = a
4 sqrt 7 = a
so 4 sqrt 7 is the length of each side