Given that the projectiles have been given by the functions:
H(t)=-16t^2+96t+80 and G(t)=31+32.2t
Part A:
The tables for the functions will be as follows:
t 2 3 4 5
H(t) 208 224 208 160
t 2 3 4 5
G(t) 95.4 127.6 159.8 198
The solution is found between points:
4th second and 5th second
i] It's between this point that the graph H(t) is has reached the maximum point and it's now turning. So the points of H(t) are nearing points for G(t).
Part B]
The solution in part A implicates the times at which the projectiles were at the same height and the time at which they were at the same heights.
X=5/9g2 but it’s a small 2 ok like g and then the 2 on top lol
Y=63x
I used Socratic and it’s never wrong
-1/2(x + 2) + 1 + 1/2 x = 3
-1/2 x - 1 + 1 + 1/2 x = 3
0 = 3
x has no solution.
