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kenny6666 [7]
3 years ago
11

CAN ANYONE HELP ME WITH THIS PLSSSSSSSSSSSSSSS

Mathematics
1 answer:
Mariana [72]3 years ago
6 0
13 is what i think
3 divided by 2= 1.5
1.5*9=13.5 and you can't score half a point so the answer is 13
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What is the answer EXPLAIN HOW YOU GOT IT FOR BRAINLEST
Paul [167]
Let's first see which box and whisker plots have a range of 17. The range is maximum-minimum. ( the last dot minus the first dot). For A. 20 - 4 = 16, so it can't be A. For B. 36-2 = 34, so it can't be B. For C. 36 - 19 = 17, so it could be C. And for D. 17 - 2 = 15, so it can't be D. C. must be the correct answer, but let's check if the interquartile range is 5. The IQR ( interquartile range) is the 3rd Quartile - the 1st Quartile. 33- 28 = 5. So, C. is the correct answer! Hope this helped!
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3 years ago
Simplify each expression by using the Distributive Property and combine like terms to simplify the expression.-2(-x-1)-(x+9)
Ymorist [56]

-2(-x-1)-(x+9)

= -2x + 2 - x - 9

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8 0
1 year ago
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S_A_V [24]

Answer:

61 degrees

Step-by-step explanation:

==>Given ∆MNO,

MO = 18,

MN = 6

m<O = 17°

==>Required:

Measure of <N

==>SOLUTION:

Use the sine formula for finding measure of angles which is given as: Sine A/a = Sine B/b = Sine C/c

Where,

Sine A = 17°

a = 6

Sine B = N

b = 18

Thus,

sin(17)/6 = sin(N)/18

Cross multiply

sin(17)*18 = sin(N)*6

0.2924*18 = 6*sin(N)

5.2632 = 6*sin(N)

Divide both sides by 6

5.2632/6 = sin(N)

0.8772 = sin(N)

sin(N) = 0.8772

N = sin^-1(0.8772)

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8 0
3 years ago
Restaurateur Denny Valentine is evaluating two sites, Raymondville and Rosenberg, for his next restaurant. He wants to prove tha
Aleksandr-060686 [28]

Answer:

\bar X_1 represent the sample for the sample 1

\bar X_2 represent the sample for the sample 2

s_1 represent the deviation for the sample 1

s_2 represent the deviation for the sample 2  

n_1 = 81 represent the sample size for the group 1

n_2 = 81 represent the sample size for the group 2

And on this case if we create the system of hypothesis we have this:

Null hypothesis :\mu_1 -\mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2 >0

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".  

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".  

On this caseHe wants to prove that Raymondville residents (population 1) dine out more often than Rosenberg residents (population 2). So this statement need to be on the alternative hypothesis. And the complement of the alternative hypothesis would be on the null hypothesis.  

Solution to the problem

We assume that we have the following statistics:

\bar X_1 represent the sample for the sample 1

\bar X_2 represent the sample for the sample 2

s_1 represent the deviation for the sample 1

s_2 represent the deviation for the sample 2  

n_1 = 81 represent the sample size for the group 1

n_2 = 81 represent the sample size for the group 2

And on this case if we create the system of hypothesis we have this:

Null hypothesis :\mu_1 -\mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2 >0

5 0
4 years ago
What is 2 over seven times five over six?
sukhopar [10]
In its exact form 5/21



5 0
3 years ago
Read 2 more answers
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