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Maksim231197 [3]
3 years ago
12

(I) At room temperature, an oxygen molecule, with mass of –26 5.31 10 kg, typically has a kinetic energy of about –21 6.21 10 J

. How fast is it moving?
Physics
1 answer:
Fofino [41]3 years ago
7 0

Answer:

0.484 m/s

Explanation:

Kinetic energy is given by

KE = mv²/2

m = mass of the oxygen molecule = 5.31 x 10⁻²⁰ kg

K.E = kinetic energy of the oxygen molecule = 6.21 x 10⁻²¹ J

v = ?

(6.21 x 10⁻²¹) = (5.31 x 10⁻²⁰) v²/2

v² = 2 × (6.21 x 10⁻²¹)/(5.31 x 10⁻²⁰) = 0.2339

v = 0.484 m/s

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Answer:

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<em></em>

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