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Amanda [17]
3 years ago
9

Which is correct? I need to know!!

Physics
1 answer:
Mnenie [13.5K]3 years ago
6 0
What website are you using?
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An upward moving object must be experiencing (or at least usually does experience) an upward force.
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Gravity pulls objects down to the earth
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Radio devices are used for communication in space. Why
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Because radio waves can travel in space but sound waves cannot.
6 0
3 years ago
3. A penguin waddles 8 m uphill before sliding back down to its friends in 2 seconds. If the penguin ends where it started, what
german

The velocity of penguin as he ends where he started was 0 m/s.

<h3>What is displacement?</h3>

Displacement is the length of straight line joining the initial and final position of the body.

Given is a penguin who waddled 8 m uphill before sliding back down to its friends in 2 seconds.

We know that the velocity is the rate of change of displacement with respect to time. Mathematically -

v = dx/dt

dx = v dt

∫dx = ∫v dt

Δx = vΔt

v = Δx/Δt

Now, the displacement of the penguin will be = Δx = 8 - 8 = 0

Then, its velocity will be -

v = 0/Δt = 0

Therefore, the velocity of penguin as he ends where he started was 0 m/s.

To solve more questions on kinematics, visit the link below-

brainly.com/question/27200847

#SPJ1

4 0
1 year ago
A motor exerts a force of 12,00N to lift an elevator 8.0m in 7.0secs what is the power produced by the motor?
SashulF [63]

Answer:

1371.4watt

Explanation:

from power=energy/time

BUT energy=force times distance

6 0
3 years ago
A distant planet with a mass of (7.2000x10^26) has a moon with a mass of (5.0000x10^23). The distance between the planet and the
BARSIC [14]

Answer:

Explanation:

This is a simple gravitational force problem using the equation:

F_g=\frac{Gm_1m_2}{r^2} where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.

Filling in:

F_g=\frac{(6.67*19^{-11})(7.2000*10^{26})(5.0000*10^{23})}{(6.10*10^{11})^2} I'm going to do the math on the top and then on the bottom and divide at the end.

F_g=\frac{2.4012*10^{40}}{3.721*10^{23}} and now when I divide I will express my answer to the correct number of sig dig's:

Fg= 6.45 × 10¹⁶ N

8 0
3 years ago
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